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Kamila [148]
4 years ago
13

le=" - 10 \times 18 {r}^{ - 8} = - 2" alt=" - 10 \times 18 {r}^{ - 8} = - 2" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
grigory [225]4 years ago
3 0

Answer:

1.107   =  r

Step-by-step explanation:

To solve this for r, do the following:

Add 10 to both sides, to isolate the r term on the left:  18r^(-8) = 8

Divide both sides by 18, to isolate r^(-8):   r^(-8) = 8/18

Invert both sides:  r^8 = 9/4

Take the natural log or both sides:

8 ln r = ln 9 - ln 4, or

8 ln r = 0.8109, so that ln r = 0.1014

to find r, raise e to the power ln r on the left and e to the power 0.1014 on the right:

  ln r           0.1014

e         =    e              =  1.107   =  r

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Which expressions are equivalent to (4⋅a)⋅2 Drag and drop the equivalent expressions into the box. A. 4 x (a x 2) B. 4x2xax2 C 8
aksik [14]

(4*a)*2

lets give a a number: a = 3 so (4*3)*2  = 12*2 = 24

 lets try the options:

A) 4 *(3*2) = 4*6 = 24 = the same

B) 4*2*3*2 = 8*3*2 = 24*2 = 48 = different

C) 8*3 = 24 = same

D) 4*2+3*2 = 8 +6 = 14 = different

E) 2*(4*3) = 2*12 = 24 = same


 so A, C & E would be the equivalent.


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4 years ago
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sergij07 [2.7K]
The answer is B) if the need is already fulfilled
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4 years ago
A specific brand of gourmet chocolate candy contains 7.00 gg of dietary fat in each 22.7-gg piece. How many kilograms of dietary
Oduvanchick [21]

Answer:

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Step-by-step explanation:

A gourmet chocolate candy has 7.00 gg of dietary fat in each 22.7-gg piece

for the 22.7 piece , the gg is 7 x 22.7  = 158.9gg in total

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for the box of 4.00 lblb of candy

it is 350314534.612 x 4 = 1401258138.45lb

since our answer is needed in kilograms we convert 1401258138.45lb to kilograms

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4 years ago
If a right triangle's hypotenuse is 17 units long, and one of its legs is 15 units long, how long is the other leg?
Vesna [10]

Answer:

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Step-by-step explanation:

Hello!

So, there's a formula we can apply to right-angled triangles: Pythagorean's theorem. It states that  c = \sqrt{{a}^2 + b^{2} }, where <em>c</em> is the hypotenuse and <em>a</em> and <em>b </em>are the legs of the triangle.

So, from the problem,  if <em>c </em>= 17 and <em>a </em> = 15, then, we're solving for <em>b</em>. So we'll rewrite the theorem to solve for <em>b</em>.

{c}^2 = {a}^2+{b}^2\\{c}^2-{a}^2={b}^2\\{b} = \sqrt{{c}^2-{a}^2}

Okay, so now we have isolated the theorem for <em>b. Let's </em>plug in our values for <em>c </em>and <em>a</em>.

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<em />c = \sqrt{{a}^2+{b}^2}}\\c = \sqrt{{15}^2+{8}^2}\\c = \sqrt{225+64}\\c = \sqrt{289}\\c = 17\\<em />

So, we got our hypotenuse to equal 17 units, which is correct! So, our <em>b</em> is correct too. Awesome

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Answer:

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