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dolphi86 [110]
3 years ago
12

Can someone help me with this? Supposed to go off of the graph to fill in the sentence stems

Mathematics
1 answer:
Jobisdone [24]3 years ago
4 0

Answer:

Step-by-step explanation:

i don't see the thing you put it just shows the question

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54 is 150% of what number?
Sladkaya [172]
54 ..........150%
x .............100%

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Please please help me...
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3 years ago
To help vegetables stay fresh longer, Liam’s family maintains storage near their home. The total volume of the root cellar is 95
Helga [31]

To help vegetables stay fresh longer, Volume of storage of 951 cubic feet is equal to 26.929 m^3

<u>Solution:</u>

Given that to help vegetables stay fresh longer, Liam’s family maintains storage.

Total volume of root cellar that is storage is 951 cubic feet.

Also given that 1 foot = 0.3048 meters

need to find the volume of storage in cubic meter that is m^3

\begin{array}{l}{\text { As } 1 \text { foot }=0.3048 \mathrm{m}} \\\\ {\Rightarrow 1 \text { foot } \times 1 \text { foot }=0.3048 \mathrm{m} \times 0.3048 \mathrm{m}} \\\\ {\Rightarrow 1 \text { foot } \times 1 \text { foot } \times 1 \text { foot }=0.3048 \mathrm{m} \times 0.3048 \mathrm{m} \times 0.3048 \mathrm{m}} \\\\ {=1 \mathrm{foot}^{3}=0.0283 \mathrm{m}^{3}} \\\\ {\Rightarrow 1 \text { cubic feet }=0.0283 \mathrm{m}^{3}}\end{array}

\text { So } 951 \text { cubic feet }=951 \times 0.0283 \mathrm{m}^{3}=26.929 \mathrm{m}^{3}

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7 0
3 years ago
In a horse race with 5 horses, you make a bet by predicting the ranking of all 5 horses. Suppose you place your bet at random. W
lapo4ka [179]

Answer:

P( top two horses are predicted incorrectly in incorrect order)

= \frac{1}{2}

Step-by-step explanation:

In the horse race the outcome can be predicted in 5! = 120 ways.

Now suppose the top two horses were predicted incorrectly in incorrect order. Now, the  top horse can be predicted incorrectly in 4 ways.

Suppose the top horse was predicted to be in k-th position where k = 2, 3 ,4,5

so the second horse can be predicted to be in place from 1 to (k - 1)

So, the top two horses can be predicted  incorrectly in incorrect order

in \sum_{k =2}^{5}(k - 1) = 10 ways  

and for each prediction of the two the remaining horses may be predicted in 3! = 6 ways.

Hence ,

P( top two horses are predicted incorrectly in incorrect order)

= \frac{6 \times 10}{120}

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