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Ilya [14]
2 years ago
6

3. Find the standard form of the equation of the parabola with a vertex at the origin and a focus at (0-4).

Mathematics
1 answer:
ch4aika [34]2 years ago
5 0

Step-by-step explanation:

y=5(x+1/5)² -36/5

y=5(x+1/5)² -36/5

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Answer:

<em>The slope of the line is -1</em>

Step-by-step explanation:

<u>Slope of a Line</u>

Suppose we know a given line passes through points A(x1,y1) and B(x2,y2). The slope can be calculated as follows:

\displaystyle m=\frac{y_2-y_1}{x_2-x_1}

From the table in the image, we select the points (1,4) (3,2). The slope is:

\displaystyle m=\frac{2-4}{3-1}=\frac{-2}{2}=-1

Now select two other points like (5,0) (7,-2)

\displaystyle m=\frac{-2-0}{7-5}=\frac{-2}{2}=-1

Following the same procedure with any other pair of points, we'll get the very same result:

The slope of the line is -1

4 0
4 years ago
#1. Which is equal to z3 8? A. (z - 2)(z^2 - 2z - 4). B. (z + 2)(z^2 - 2z + 4) C.(z - 2)(z^2+ 2z + 4). D. (z + 2)(z^2+ 2z - 4) #
tankabanditka [31]
#1. B
<span>(z * z^2 + z * 2z + z * 4) – (-2 *z^2 – (-2) 2z – (-2) 4)
Z^3 + 2z^2 + 4z – 2z^2 -4z – 8
Z^3 + 2z^2 – 2z^2 + 4z – 4z – 8
Z^3 - 8
</span>
#2 and #3. D
<span>(x + y)(x + 2)
x^2 + 2x + yx + 2y
</span>
#4. D.
<span>(x - 7)(x + 7)(x- 2)
x^2 + 7x – 7x -49
x^2 + x – 49
x^2 -49
(x^2 – 49 ) (x – 2)
x^3 – 2x^2 – 49x + 98
</span>
#5. C
(y - 4) = 0
y = 4
(x + 3)= 0
x = -3

#6. A and B
3 0
3 years ago
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