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3 years ago

Which expression is equivalent to ( 2/5 x + 1 1/5)?

1 answer:

3 0

First you make 1 1/5 an mixed fraction by multiplying 1 times 5 and add one which gives you 6/5 and then you don't add because 2/5 has a variable so you can't combine like terms if you don't have like terms so my answer would be 2/5x + 6/5 but you can wait to answer incase someone else answers incase I'm wrong but just helping :)

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A new mixture of self-tanning & moisturizing lotions for everyday use is being developed. This mixture is made by mixing 90

butalik [34]

I don't know but i need points so thanks

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3 years ago

Expand and simplify <br><br> 3(c-7)+2(3c+4)

leonid [27]

Answer:

9c - 13

Step-by-step explanation:

Given

3(c - 7) + 2(3c + 4) ← distribute both parenthesis

= 3c - 21 + 6c + 8 ← collect like terms

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2 years ago

Read 2 more answers

Solve for k, 6k-2z=12

Alenkinab [10]

The previous question I answered was exactly like this.

6(4) - 2(6) = 12.

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3 years ago

What are the x- and y-intercepts of 2x+4y=8

NeX [460]

x-intercept: (4,0)

y-intercept: (0,2)

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3 years ago

A contractor is in charge of hiring people for a construction project. The number of days it would take to complete the project

sweet-ann [11.9K]

Answer:

$\text{Domain of x}=[1,\infty), x \in Z^+$

Step-by-step explanation:

Given the function: $f(x)=\dfrac{280}{x},$ where:$

f(x) =number of days it would take to complete the project

x =number of full-time workers.

$\text{When x=0, }f(x)=\dfrac{280}{0}=$Undetermined\\\text{When x=1, }f(x)=\dfrac{280}{1}=$280 days\\\text{When x=280, }f(x)=\dfrac{280}{280}=$1 day\\\text{When x=560, }f(x)=\dfrac{280}{560}=$0.5 days$

The domain of a function is the complete set of possible values of the independent variable.

In this case, the independent variable is x, the number of full-time workers. We have shown that x cannot be zero as there must be at least a worker on ground.

Therefore, an appropriate domain of the function f(x) is the set of positive integers (from 1 to infinity).

$\text{Domain of x}=[1,\infty), x \in Z^+$

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3 years ago