5A + 7 = 3A + 7 + 2A
We need to solve for A.
3A + 7 + 2A = 3A + 2A + 7 = 5A + 7 (We can add 3A and 2A because it's the same variable, so we add the coefficients)
5A + 7 = 3A + 7 + 2A
5A + 7 = 5A + 7
5A + 7 is always equal to 5A + 7 because it's the same equation. So the equation got infinitely many solutions.
If we draw the contingency table of x (vertical) against y (horiz.), we have a square.
For n=4, we have (legend: < : x<y = : x=y > : x>y
y 1 2 3 4
x
1 = < < <
2 > = < <
3 > > = <
4 > > > =
We see that there are n(n-1)/2 cases of x<y out of n^2.
Therefore,
p(x<y)=n(n-1)/(2n^2)=(n-1)/(2n)
However, if the sample space is continuous, it will be simply p(x<y)=1/2.
Answer:
the answer is A. -16
Step-by-step explanation:
3(-16)+3= -45
-45/5=
-9
5(-16)-1=-81
-81/9=
-9
-9=-9
This fraction cannot be changed to a mixed number because 3 can divide 42 to give 14. Hope i helped. Have a nice day.
