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Xelga [282]
3 years ago
11

You invest $300 at 4% interest, compounded every year. What will your balance be after 5 years? (Remember, the formula is A = P(

1 + r)t.)
A. $364.65

B. $382.88

C. $365.00

D. $350.96
Mathematics
1 answer:
Stells [14]3 years ago
3 0

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill\\ P=\textit{original amount deposited}\to &\$300\\ r=rate\to 4\%\to \frac{4}{100}\to &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{every year, once} \end{array}\to &1\\ t=years\to &5 \end{cases} \\\\\\ A=300\left(1+\frac{0.04}{1}\right)^{1\cdot 5}\implies A=300(1.04)^5\implies A\approx 364.996

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What is the slope intercept form of the equation for the line that has a slope of -2 and a y-intercept of 3?
Misha Larkins [42]

Answer:

y = - 2x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = - 2 and c = 3, hence

y = - 2x + 3 ← equation in slope- intercept form

7 0
3 years ago
Can someone help me plz
Karo-lina-s [1.5K]

Answer:

y = 2x - 10

Step-by-step explanation:

The slope is 4 + 4 / 7 - 3 = 8 / 4 = 2

y = 2x + b

-4 = 6 + b

b = -10

Thank, 5 star, braniliest if helpful

3 0
3 years ago
Please help and thanks ​
pav-90 [236]

Answer: Bottom left corner

Angle DEC and Angle DEH

=============================================================

Explanation:

I recommend opening your favorite paint program, and using different colors to mark on the drawing as I have done below (see attached image). Note how angle DEC is in red and angle DEH is in blue. The two angles are adjacent, meaning they share the same ray (in this case, ray ED) and they form a straight angle.

Because they form a straight angle, or straight line, this means the two angles are supplementary. Supplementary angles always add to 180.

4 0
3 years ago
A flagpole is at the top of a building. 300 feet from the base of the building, the angle of elevation of the top of the pole is
Grace [21]

Answer: We can use tangent here to find the length of the flagpole

First, find the length of the building + the flag pole

tan 32 = x/300

x=300tan32=187.460805573

(length of building + flagpole)

find length of building

tan 30 = x/300

x=173.205080757

subtract

187.460805573-173.205080757=14.255724816

round, length of flagpole = 14 feet

7 0
3 years ago
PLEASE HELP!!! Find the equation , in the standard form of the line passing through the points (3,-4) and (5,1)
ExtremeBDS [4]
\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ 3 &,& -4~) 
%  (c,d)
&&(~ 5 &,& 1~)
\end{array}
\\\\\\
% slope  = m
slope =  m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-(-4)}{5-3}\implies \cfrac{1+4}{5-3}\implies \cfrac{5}{2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-(-4)=\cfrac{5}{2}(x-3)\implies y+4=\cfrac{5}{2}x-\cfrac{15}{2}

\bf y=\cfrac{5}{2}x-\cfrac{15}{2}-4\implies y=\cfrac{5}{2}x-\cfrac{23}{2}\impliedby 
\begin{array}{llll}
\textit{now let's multiply both}\\
\textit{sides by }\stackrel{LCD}{2}
\end{array}
\\\\\\
2(y)=2\left( \cfrac{5}{2}x-\cfrac{23}{2} \right)\implies 2y=5x-23\implies \stackrel{standard~form}{-5x+2y=-23}
\\\\\\
\textit{and if we multiply both sides by -1}\qquad 5x-2y=23

side note:  multiplying by the LCD of both sides is just to get rid of the denominators
5 0
3 years ago
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