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Xelga [282]
3 years ago
11

You invest $300 at 4% interest, compounded every year. What will your balance be after 5 years? (Remember, the formula is A = P(

1 + r)t.)
A. $364.65

B. $382.88

C. $365.00

D. $350.96
Mathematics
1 answer:
Stells [14]3 years ago
3 0

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill\\ P=\textit{original amount deposited}\to &\$300\\ r=rate\to 4\%\to \frac{4}{100}\to &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{every year, once} \end{array}\to &1\\ t=years\to &5 \end{cases} \\\\\\ A=300\left(1+\frac{0.04}{1}\right)^{1\cdot 5}\implies A=300(1.04)^5\implies A\approx 364.996

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Which angle is an x–intercept for the function y=cos(1/2x)? A. 0 B. pie/2 C. pie D. 2pie
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Answer:

For the function

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Step-by-step explanation:

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Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

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So, to calculate electric fields, we need to find the proper equation to do so: E=k\frac{q}{r^{2} }; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: p=\frac{q}{A}; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: S=4\pi r^{2}; which gives us the surface of a sphere.

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The outer surface: S=4\pi (0.08m)^{2}=0.08m^{2}

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Outer charge: Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC

Then, we are able to calculate both fields:

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The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

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