this is kinda easy and im gonna assume that the 4 is a exponent cuz f(2)=2(3)^4 then f=81
Answer:
x = 
Step-by-step explanation:
Given
x +
+ (x - 1) = 
Multiply through by 10 ( the LCM of 2 and 5 ) to clear the fractions
10x + 15 + 10(x - 1) = 8
10x + 15 + 10x - 10 = 8
20x + 5 = 8 ( subtract 5 from both sides )
20x = 3 ( divide both sides by 20 )
x = 
Answer:
( x-3) ^2 + ( y-1) ^2 = 4
Step-by-step explanation:
The equation for a circle is given by
( x-h)^2 + ( y-k) ^2 = r^2 where (h,k) is the center and r is the radius
( x-3) ^2 + ( y-1) ^2 = 2^2
( x-3) ^2 + ( y-1) ^2 = 4
Answer:
The answer to your question is the second option, both coordinates should be negative.
Step-by-step explanation:
The point Hassam plotted was (-0.5, -0.25). If he wanted to plot point (0.5, 0.25):
-First, he should have counted two squares to the right
- then one square up.
Because both coordinates are positive this point must be in the first quadrangle not in the third.
Step-by-step explanation:
Line A : x + y = 2
The most likely equation for line B so that the set of equation has no solution is:
x + y = 4
====
x + y = 2
x = 2 - y
2-y + y = 4
0 = 4 - 2
0 ≠ 2
there is no value for x nor y. so, no solution.