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amm1812
3 years ago
11

If 8=10 and 1=7,which describes all the lines that must be parallel?

Mathematics
1 answer:
agasfer [191]3 years ago
6 0

Answer:

C

Step-by-step explanation:

For the above statement to hold we must have two sets of parallel lines; that is:

r and s , and then t and u.

These lines form corresponding and alternate angles.

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A ship sails on a bearing of 020° for 30 km.
zepelin [54]

Answer:

The ship travels approximately 10.261 meters to the East.

Step-by-step explanation:

At first we introduce a graphical description of the statement as an attachment below. Let suppose that bearing is respect to the North-direction, then the change in position in the East direction is modelled by the following Trigonometric formula:

x = r\cdot \sin \theta (1)

Where:

r - Distance travelled by the ship, measured in kilometers.

\theta - Bearing angle, measured in sexagesimal degrees.

x - Distance component in the east direction, measured in kilometers.

If we know that r = 30\,km and \theta = 20^{\circ}, then the distance in the East direction is:

x = (30\,km)\cdot \sin 20^{\circ}

x \approx 10.261\,m

The ship travels approximately 10.261 meters to the East.

7 0
3 years ago
Question in link. Please help :(
attashe74 [19]

Answer:

The median

Step-by-step explanation:

It uses all the added numbers as one

6 0
3 years ago
What is the least common multiple of 8 and 6?
Degger [83]

Answer:

24

Step-by-step explanation:

8 16 24 32 40...

6 12 18 24 30 36....

24 and 24.

4 0
3 years ago
Helpppppppppppppppppppp
Sliva [168]
a_1=11+(1-1)(4)=11+0=11\\\\a_2=11+(2-1)(4)=11+4=15

so:

a_2=a_1+\,?\\\\15=11+\,?\\\\\boxed{?=4}

Answer B.
8 0
3 years ago
Find the quotient of these Complex Numbers. <br><br><br> (5-i) / (3+2i)
JulsSmile [24]

Let the given complex number

z = x + ix = \dfrac{5-i}{3+2i}

We have to find the standard form of complex number.

Solution:

∴ x + iy = \dfrac{5-i}{3+2i}

Rationalising numerator part of complex number, we get

x + iy = \dfrac{5-i}{3+2i}\times \dfrac{3-2i}{3-2i}

⇒ x + iy = \dfrac{(5-i)(3-2i)}{3^2-(2i)^2}

Using the algebraic identity:

(a + b)(a - b) = a^{2} - b^{2}

⇒ x + iy = \dfrac{15-10i-3i+2i^2}{9-4i^2}

⇒ x + iy = \dfrac{15-13i+2(-1)}{9-4(-1)} [ ∵ i^{2} =-1]

⇒ x + iy = \dfrac{15-2-13i}{9+4}

⇒ x + iy = \dfrac{13-13i}{13}

⇒ x + iy = \dfrac{13(1-i)}{13}

⇒ x + iy = 1 - i

Thus, the given complex number in standard form as "1 - i".

5 0
3 years ago
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