Construct a Rational Function that has a vertical asymptote at X = 6, and a removable

Mathematics

1 answer:

Schach [20]3 years ago

8 0

Answer:

(x+2)/(x-6)(x+2)

Step-by-step explanation:

We know that vertical asymptotes are found in the denominator, so we can start with 1/(x-6)

x-6 will equal zero at 6, so that is where the VA will be.

For the removable discontinuity (hole), it needs to cancel out in the numerator and denominator. (x+2)/(x-6)(x+2)

when x equals -2, there is an undefined y value.

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