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Olenka [21]
3 years ago
5

Square root of 16÷4^3=4^n

Mathematics
1 answer:
nata0808 [166]3 years ago
8 0

Answer:

n = -½

Explanation:

\sqrt{\frac{16 }{4^{3}} } = 4^{n}     Express 16 as 4²

\sqrt{\frac{4^{2}}{4^{3}}} = 4^{n}     Do the division

\sqrt{4^{-1}} = 4^{n}     Square both sides

4^{-1} = 4^{2n}    Take log₄ of both sides  

-1 = 2n     Divide each side by 2  

n = -\frac{1 }{ 2}

===============

<em>Check</em>:

\sqrt{\frac{16 }{4^{3}} } = 4^{-\frac{ 1}{ 2}}

\sqrt{\frac{16}{ 64}} = \frac{1 }{4^{\frac{1 }{ 2}}}

\sqrt{\frac{1}{4}} = \sqrt{\frac{1}{4}}

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Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z
kompoz [17]

a.

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is a proper joint density function if, over its support, f is non-negative and the integral of f is 1. The first condition is easily met as long as C\ge0. To meet the second condition, we require

\displaystyle\int_0^\infty\int_0^\infty\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz=100C=1\implies \boxed{C=0.01}

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f_{X,Y}(x,y)=\displaystyle\int_0^\infty f_{X,Y,Z}(x,y,z)\,\mathrm dz=0.01e^{-(0.5x+0.2y)}\int_0^\infty e^{-0.1z}\,\mathrm dz

\implies f_{X,Y}(x,y)=\begin{cases}0.1e^{-(0.5x+0.2y)}&\text{for }x\ge0,y\ge0\\0&\text{otherwise}\end{cases}

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\displaystyle P(X\le1.375,Y\le1.5)=\int_0^{1.5}\int_0^{1.375}f_{X,Y}(x,y)\,\mathrm dx\,\mathrm dy

\approx\boxed{0.12886}

c. This probability can be found by simply integrating the joint density:

\displaystyle P(X\le1.375,Y\le1.5,Z\le1)=\int_0^1\int_0^{1.5}\int_0^{1.375}f_{X,Y,Z}(x,y,z)\,\mathrm dx\,\mathrm dy\,\mathrm dz

\approx\boxed{0.012262}

7 0
3 years ago
Kapil needed to buy a long wooden beam. He went to two sawmills that each charge an initial fee plus an additional fee for each
matrenka [14]

Answer: first sawmill charges more for each meter of wood. And first mill has a cheaper price for 5-meter wooden beam.

Step-by-step explanation:

P=5+20x. The first sawmill charges $20. Then 110-20/5-0=18 Which means The second sawmill charges $18 for each meter of wood. Since 20>18 The first sawmill charges more for each meter of wood.

P = 5+20x

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The first mill charges $105 For a 5 meter beam while the second beam charges $110

7 0
4 years ago
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