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denis-greek [22]
3 years ago
15

Based on the graph below, what is the domain and range of the function?

Mathematics
2 answers:
Citrus2011 [14]3 years ago
8 0

Answer:

Domain = all real numbers

Range = y ≥ -4

Step-by-step explanation:

Domain is the x-values, and for parabolas it is almost always all real numbers.

Range is the y-values, and the lowest it gets is -4.

NeTakaya3 years ago
7 0

Answer:

The f(x) domain is the set of all values for the function and the function spectrum is the set of all values for which f is defined.

Step-by-step explanation:

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2 years ago
Me ayudan alguien/ can someone help me!!!​
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Answer:

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Step-by-step explanation:

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7 0
3 years ago
A salad bar offers vegetable platters in 4 sizes (small, medium, large, and super-sized) and 6 different vegetables to choose fr
quester [9]

Answer: She could create 60 platters.

Step-by-step explanation:

Given: A salad bar offers vegetable platters in 4 sizes (small, medium, large, and super-sized) and 6 different vegetables to choose from.

Number of combinations of selecting <em>r</em> things from <em>n</em> things is given by:-

^nC_r=\dfrac{n!}{r!(n-r)!}

So, the number of combinations of selecting 2 different vegetables from 6 = ^6C_2=\dfrac{6!}{2!4!}=\dfrac{6\times5}{2}=15

Now, By Fundamental counting principle, the number of different platters she could create = (number of ways of selecting 2 different vegetables from 6) x (Number of sizes)

= 15 x 4

= 60

Hence, she could create 60 platters.

6 0
3 years ago
On the photo /picture
asambeis [7]

We need to compute the diagonal of yhe square.

d²=7²+7²=49×2cm²

d=7×sqrt(2)=7×1.41=9.87cm.

The diagonal we just computed is the diameter of the circle that contains the square.

Since d=9.87 < 11, then indeed, the square fits inside the circle, without touching it.

6 0
3 years ago
7/10 of 120 and show work pls
slavikrds [6]
When it says 7/10, it actually means 70%, so you have to find 70% of 120.
<span>
70 % of 120 
= 70% x 120 
= (70/100) x 120 
= (8400/100) 
= 84

Answer: 84</span>
8 0
3 years ago
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