Answer:
Value of x maximising profit : x = 5
Explanation:
Cost : C(x) = x^3 - 6x^2 + 13x + 15 ; Revenue: R(x) = 28x
Profit : Revenue - Cost = R(x) - C(x)
28x - [x^3 - 6x^2 + 13x + 15] = 28x - x^3 + 6x^2 - 13x - 15
= - x^3 + 6x^2 + 15x - 15
To find value of 'x' that maximises total profit , we differentiate total profit function with respect to x & find that x value.
dTP/dx = - 3x^2 + 12x + 15 = 0 ► 3x^2 - 12x - 15 = 0
3x^2 + 3x - 15x - 15 = 0 ► 3x (x +1) - 15 (x + 1) = 0 ► (x+1) (3x-15) = 0
x + 1 = 0 ∴ x = -1 [Rejected, production quantity cant be negative] ;
3x - 15 = 0 ∴ 3x = 15 ∴ x = 15/3 = 5
Double derivate : d^2TP/dx^2 = - 6x + 12
d^2TP/dx^2 i.e - 6x + 12 at x = 5 is -6(5) + 12 = - 30+ 12 = -8 which is negative. So profit function is maximum at x = 5
Here is your answer:
Your answer is A to provide clear, balanced, and unbiased information about the topic.
Reason: When people make websites its important to have certified information so the users or people who are using the website will have verified (correct) information to use for school projects, research papers, etc...
Your answer is A.
(btw it would help to have letters on your options)
Answer:
Explanation:
From the information povided:
(a) To compute the amount of goodwill paid by Chicago Corporation
Particulars Amount ($)
Accounts Receivable 100000
Inventory 170000
Plant & Equipment 400000
Land 90000
Customer List 4000
Trade Names <u> 16000</u>
NET ASSETS (A) <u>780000</u>
<u />
Current liabilities 76000
Non-current liabilities <u>160000 </u>
NET LIABILITIES (B) <u> 236000</u>
∴
PURCHASE CONSIDERATION (A -B) 544000
<u>Less:</u> Cash Paid <u> 580000</u>
GODWILL <u> 36000 </u>
<u />
b)
In the books of Chicago Corporation, the Journal Entry to record the purchase of Naperville Company.
Account Name Dr. Cr.
Accounts Receivable A/C 100000
Inventory A/C 170000
Plant Equipment A/C 400000
Land A/C 90000
Customer List A/C 4000
Trade Names A/C 16000
Goodwill A/C 36000
Current liabilities A/C 76000
Non-Current Liabilities A/C 160000
Cash A/C 580000
c)
The minimum required amount of goodwill that Chicago can amortize by the end of 2020 is $3600.This is because the amortization can take place for a period of 10 years.
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Answer:
the amount of increase in the common stock is $75,000
Explanation:
The computation of the amount of increase in the common stock is shown below;
= Number of shares of common stock sold × stated value per share
= 15,000 shares × $5 per share
= $75,000
Hence, the amount of increase in the common stock is $75,000
Answer:
Given that,
Company's bank reconciliation at June 30 included interest earned = $150
So, it must be cash must be debited and interest revenue must be credited in the accounts.
Therefore, the journal entry is as follows:
Cash A/c Dr. $150
To Interest revenue $150
(To record the interest revenue earned)