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3 years ago

5

Kendrick Campbell purchased a $25,000 municipal bond at a quoted price of 93.456 the bond pays annual interest at a rate of 3.7%

. What is the annual interest?

1 answer:

Anastasy [175]3 years ago

4 0

The interest is $925.

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What is the value of x?<br><br><br> PLEASE HELP!!!!!!<br> Enter your answer in the box.<br><br> x =

Effectus [21]

Answer:

20

Step-by-step explanation:

3x+50 = 6x-10( opposite angles are equal)

3x = 60

x = 20

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2 years ago

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A 140-meter rope is cut into two pieces. One piece is four times as long as the other. How long is each piece?

grandymaker [24]

Answer:

28meters and 112meters

Step-by-step explanation:

one piece is x

the other is 4x

therefore; 4x+x=140

5x= 140

divide both sides by 5

x=28

4x=4(28)

=112

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2 years ago

Five times the smallest of three consecutive odd integers is seven more than twice

Fantom [35]

Answer:

5, 7, 9

Step-by-step explanation:

Using the information given we get:

$5x-7=2z$

$x+2=y\\y+2=z\\x+4=z$

$5x-7=2(x+4)\\5x-7=2x+8\\$

<em>Add 7 to both sides</em>

$5x=2x+15$

<em>Subtract 2x from both sides</em>

$3x=15$

<em>Divide both sides by 3</em>

$x=5$

Using these equations:

$x+2=y\\y+2=z\\x+4=z$

and

$x=5$

We get:

$x=5\\y=7\\z=9$

4 0

2 years ago

Pleas helppp its for a test!!!

Sedbober [7]

Answer:

what do you need help with

Step-by-step explanation:

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3 years ago

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Please help!! What is the solution to the quadratic inequality? 6x2≥10+11x

fredd [130]

Answer:

The solution of the inequation $6\cdot x^{2} \geq 10 + 11\cdot x$ is $\left(-\infty,-\frac{2}{3}\right]\cup\left[\frac{5}{2},+\infty\right)$ .

Step-by-step explanation:

First of all, let simplify and factorize the resulting polynomial:

$6\cdot x^{2} \geq 10 + 11\cdot x$

$6\cdot x^{2}-11\cdot x -10 \geq 0$

$6\cdot \left(x^{2}-\frac{11}{6}\cdot x -\frac{10}{6} \right)\geq 0$

Roots are found by Quadratic Formula:

$r_{1,2} = \frac{\left[-\left(-\frac{11}{6}\right)\pm \sqrt{\left(-\frac{11}{6} \right)^{2}-4\cdot (1)\cdot \left(-\frac{10}{6} \right)} \right]}{2\cdot (1)}$

$r_{1} = \frac{5}{2}$ and $r_{2} = -\frac{2}{3}$

Then, the factorized form of the inequation is:

$6\cdot \left(x-\frac{5}{2}\right)\cdot \left(x+\frac{2}{3} \right)\geq 0$

By Real Algebra, there are two condition that fulfill the inequation:

a) $x-\frac{5}{2} \geq 0 \,\wedge\,x+\frac{2}{3}\geq 0$

$x \geq \frac{5}{2}\,\wedge\,x \geq-\frac{2}{3}$

$x \geq \frac{5}{2}$

b) $x-\frac{5}{2} \leq 0 \,\wedge\,x+\frac{2}{3}\leq 0$

$x \leq \frac{5}{2}\,\wedge\,x\leq-\frac{2}{3}$

$x\leq -\frac{2}{3}$

The solution of the inequation $6\cdot x^{2} \geq 10 + 11\cdot x$ is $\left(-\infty,-\frac{2}{3}\right]\cup\left[\frac{5}{2},+\infty\right)$ .

3 0

3 years ago