Answer:
Step-by-step explanation:
f * g = (x^2 + 3x - 4) (x+4)
open bracket
x((x^2 + 3x - 4) + 4 (x^2 + 3x - 4)
x³ +3x²-4x+x²+12x-16
x³+3x²+x²-4x+12x-16
x³+4x²+8x-16 (domain is all real numbers.
f/g = (x^2 + 3x - 4)/(x+4)
factorising (x^2 + 3x - 4)
x²+4x-x_4
x(x+4) -1 (x+4)
(x+4)(x-1)
f/g = (x^2 + 3x - 4)/(x+4) =(x+4)(x-1)/(x+4) = (x-1)
Before factorisation, this was a rational function so the domain is all real numbers excluding any value that would make the denominator equal zero.
Hence I got x - 1, and x cannot equal -4
So the domain is just all real numbers without -4
Let the required number is 2x ,
According to the condition,
➡ 10 times the sum of half of 2x and 6 = 8
Therefore the value of x is -5.2
And, required number is -5.2
Given expression is
Now we need to simplify this expression. We can begin by factoring numerator and denominator if possible.
divide numerator and denominator both by 2v
Hence final answer is 
Or you can also keep factored form
Been a while since I've done this, but I think I remember what to do here:
The main technique is called "rise over run." The first number, the rise, is how far up the next dot on the right should be. The other number, the run, is how many spaces right the dot should be at. 1+(-2)=-1 and 8+3=11. The next dot on the right should be placed at (11,-1). If you're looking on the left, replace the addition with subtraction. 1-(-2)=3 and 8-3=5. The dot on the left should be (5,3). This means that the three dots on the slope are, in order, (5,3), (1,8), and (11,-1). To find the numbers after the third dot and before the first dot, simply repeat their respective equations.
I hope my memory was correct. Lol
