<span>t^-6 * t^2
= t^-4
hope it helps</span>
Answer:
sin A = 12 /13
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
sin A = opp / hyp
sin A = 12 /13
Let 1st integer = xLet 2nd integer = x + 1 We set up an equation. x(x + 1) = 195 x2 + x = 195 x2 + x - 195 = 0
We will use the quadratic formula: x = (-b ± √(b2 - 4ac) / (2a) x = (-1 ± √(1 - 4(-195))) / 2 x = (-1 ± √(781)) / 2 x = (-1 ± 27.95) / 2 x = 13.48x = -14.78
<span>We determine which value of x when substituted gives us a product of 195.</span> 13.48(14.48) = 195.19-14.48(-13.48) = 195.19 <span>The solution is 2 sets of two consecutive number</span> <span>Set 1</span> The 1st consecutive integer is 13.48The 2nd consecutive integer is 14.48
<span>Set 2</span> The 1st consecutive integer is -14.48The 2nd consecutive integer is -13.48Hopefully this helped, hard work lol :)
The Answer is a b¹⁰
Simplify the following:
(a^5 b^6 b^4)/a^4
Combine powers. (a^5 b^6 b^4)/a^4 = a^(5 - 4) b^(6 + 4):
a^(5 - 4) b^(6 + 4)
5 - 4 = 1:
a b^(6 + 4)
6 + 4 = 10:
Answer: a b^10
