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3 years ago

13

Devante and Chase went shopping. Devante spent $17 less than Chase. If we let z represent how much Chase spent, write an algebra

ic expression for how much Devante spent.

1 answer:

Mrac [35]3 years ago

8 0

Answer: z-$17

Step-by-step explanation:

Z is chase and devante spent 17 less so the answer is z-17

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Nataly_w [17]

Answer:

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Step-by-step explanation:

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3 years ago

Find the equation of the line through M parallel to 3x+y=18

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Answer:

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3 years ago

Read 2 more answers

One hundred items are simultaneously put on a life test. Suppose the lifetimes

romanna [79]

Answer:

a) $\mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}$

b) $\mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}$

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( $i-1$ )st and the $ith$ failures. Then, the $T_{i}$ are independent with $\mathrm{T}_{\mathrm{i}}$ being exponential with rate $\frac{(101-i)}{200} .$

Therefore,

a) $E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]$

$=\sum_{i=1}^{5} \frac{200}{101-i}$

$\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}$

$b)$

The variance is given by, $\mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]$

$\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}$

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4 years ago

Para alavancar seus lucros, o dono de uma empresa passou a investir mais no meio digital, começando pelo seu site. Com base em u

ella [17]

Answer:

85.5 reals

Step-by-step explanation:

Aqui, usando a função de análise, queremos saber a quantidade de dinheiro que deve ser investido para fornecer o número de visualizações.

A maneira como podemos resolver isso é através da substituição. Precisamos apenas substituir F (x) na equação e resolver x, o que nos dará a idéia da quantidade de dinheiro a ser investido.

matematicamente

F (x) = 40x + 80

3500 = 40x + 80

40x = 3500-80 40x = 3420 x = 3420/40

x = 85,5 reais

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3 years ago

On a sunny day, a 4-foot red kangaroo casts a shadow that is 5 feet long. The shadow of a nearby

son4ous [18]

Answer:

16 feet

Step-by-step explanation:

Set up a proportion where x is the height of the tree:

$\frac{4}{5}$ = $\frac{x}{20}$

Cross multiply and solve for x:

5x = 80

x = 16

So, the tree is 16 feet tall

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3 years ago