3 years ago

If 4 people can stain a deck in 2 days, how many people would be required to stain the deck in only 1 day?

Mathematics

2 answers:

Nutka1998 [239]3 years ago

7 0

The answer to this is 8

Andre45 [30]3 years ago

5 0

8 people could stain a deck in one day.

You might be interested in

On his math test, Balavan wrote that a four-sided polygon that has at least two right angles must be a rectangle or a square. De

gregori [183]

A quadrilateral with only 2 right angles could be a trapezoid so Balavan is wrong. Denna is right because if 3 angles are right angles the the fourth angle must also be a right angle and has to be a square or rectangle.

4 0

2 years ago

Read 2 more answers

(100 points!)

tatyana61 [14]

Every 10 minutes of reading my book, I read 20 pages each. // part B you read 0.5 minutes per page

5 0

3 years ago

1) Erik has a job at Hobby Lobby and he

Artyom0805 [142]

Answer:

Step-by-step explanation:

is there more to this problem?

13. 00* 6 = 78

7 0

2 years ago

Which property is 5+ a = a + 5 ?

zheka24 [161]

Answer:

$commutative \: property \: of \: addition \\ thank \: you$

6 0

2 years ago

Find two positive consecutive odd integers such that square of the smaller integer is 10 more than the larger integer

Otrada [13]

Let $2n+1$ be the smaller integer. The larger integer is then $2n+3$ , and we have

$(2n+1)^2=10+(2n+3)\implies4n^2+4n+1=2n+13$

$\implies4n^2+2n-12=0$

$\implies2n^2+n-6=0$

$\implies(2n-3)(n+2)=0$

$\implies 2n-3=0\text{ or }n+2=0$

$\implies n=\dfrac32\text{ or }n=-2$

We omit $n=-2$ , since $2(-2)+1=-3$ is negative.

Then for $n=\dfrac32$ we find $2\left(\dfrac32\right)+1=4$ , but this is not odd.

There are no consecutive odd integers that satisfy the given condition!

3 0

2 years ago