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valentinak56 [21]
3 years ago
7

A projectile with an initial velocity of 48 feet per second is launched from a building 190 feet tall. The path of the projectil

e is modeled using the equation h(t) = –16t2 + 48t + 190.
What is the maximum height of the projectile?
A. 82 feet
B. 190 feet
C. 226 feet
D. 250 feet​
Mathematics
2 answers:
Bad White [126]3 years ago
7 0

Answer:

The answer is C

Step-by-step explanation:

Ghella [55]3 years ago
3 0

Answer: C: 226ft

Step-by-step explanation:

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Answer:

s = 14

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Step 1: Combine like terms.

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Step 2: Multiply both sides by 2/3.

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