The two in the middle. B and C, I guess.
Using Lagrange multipliers, we have the Lagrangian

with partial derivatives (set equal to 0)




Substituting the first three equations into the fourth allows us to solve for

:

For each possible value of

, we get two corresponding critical points at

.
At these points, respectively, we get a maximum value of

and a minimum value of

.
Answer:
Multiply it like a normal number.
Step-by-step explanation:
Take the point away in both numbers
line the numbers up and add the zero at the end of 28
multiply
add the decimal point back after solved (3 decimal points)
818
x280
-----------
2x - 3(x + 4) = -5
2x - 3x - 12 = -5
-x - 12 = -5
-x = -5 + 12
-x = 7
x = -7
The answer is: x = -7.