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2 years ago

Solve for y8×+4y=2

Mathematics

2 answers:

Zina [86]2 years ago

5 0

Answer:8

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)

Simplify the left side.

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Move all terms containing

to the left side of the equation.

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Add

to both sides of the equation.

Divide each term by

and simplify.

Step-by-step explanation:

It's 8, hope it helped <3

vichka [17]2 years ago

5 0

The answer for y is 8

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Find the surface area of the composite figure.

WINSTONCH [101]

Answer:

382 cm²

Step-by-step explanation:

Front face + Back face:

A = 2(a + b)h/2

A = 2(14 cm + 8 cm)(7 cm)/2

A = 154 cm²

Left face:

A = 7 cm × 6 cm = 42 cm²

Right face:

A = 9 cm × 6 cm = 54 cm²

Bottom face:

A = 14 cm × 6 cm = 84 cm²

Top face:

A = 6 cm × 8 cm = 48 cm²

Total surface area =

= (154 + 42 + 54 + 84 + 40) cm²

= 382 cm²

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7 months ago

The measure of one angle is 7 times the measure of its complement.Find each angle measure

aleksklad [387]

<span>let the angles be x and y.
as they are compliment
x+y=90
also given
x=7y

substituting value of x in first equation
7y+y=90
8y=90
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y=11.25
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7 0

2 years ago

Production output paid a seamstress .5 every 4 pockets sewed how many pockets she have to sew for $60.00

Sphinxa [80]

The seamstress would have to sew 15 pockets for $60. Just divide 60.00 by 4.

5 0

2 years ago

The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per

ICE Princess25 [194]

Answer:

1.76% probability that in one hour more than 5 clients arrive

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per hour.

This means that $\mu = 2$

What is the probability that in one hour more than 5 clients arrive

Either 5 or less clients arrive, or more than 5 do. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 5) + P(X > 5) = 1$

We want P(X > 5). So

$P(X > 5) = 1 - P(X \leq 5)$

In which

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353$

$P(X = 1) = \frac{e^{-2}*2^{1}}{(1)!} = 0.2707$

$P(X = 2) = \frac{e^{-2}*2^{2}}{(2)!} = 0.2707$

$P(X = 3) = \frac{e^{-2}*2^{3}}{(3)!} = 0.1804$

$P(X = 4) = \frac{e^{-2}*2^{4}}{(4)!} = 0.0902$

$P(X = 5) = \frac{e^{-2}*2^{5}}{(5)!} = 0.0361$

$P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1353 + 0.2702 + 0.2702 + 0.1804 + 0.0902 + 0.0361 = 0.9824$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9824 = 0.0176$

1.76% probability that in one hour more than 5 clients arrive

8 0

2 years ago

Read 2 more answers

Explain how the Quotient of Powers was used to simplify this expression. 2 to the fifth power, over 8 = 22 By finding the quotie

astraxan [27]

Answer:

we can do it by simplifying 8 to $2^3$ to make both powers base two, and subtracting the exponents.

Step-by-step explanation:

We have been given the expression $\frac{2^5}{8}=2^2$

8 can be rewritten as $2^3$

Hence, the given expression becomes

$\frac{2^5}{2^3}=2^2$

After subtracting the exponents on left hand side of the equation we get:

$2^2=2^2$

we can do it by simplifying 8 to $2^3$ to make both powers base two, and subtracting the exponents.

6 0

3 years ago

Read 2 more answers

Solve for y8×+4y=2​

Solve for y8×+4y=2