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Furkat [3]
3 years ago
12

A square matrix A is idempotent if A2=A. Let V be the vector space of all 2×2 matrices with real entries. Let H be the set of al

l 2×2 idempotent matrices with real entries. Is H a subspace of the vector space V?
Mathematics
1 answer:
igomit [66]3 years ago
5 0

Answer:

No, H is not a subspace of the vector space V.

Step-by-step explanation:

A matrix is a rectangular array in which elements are arranged in rows and columns.

A matrix in which number of columns is equal to number of rows is known as a square matrix.

Let H denote set of all 2×2  idempotent matrices.

H is a subspace of a vector space V if u+v \in H for u,v \in V and   cu \in H.

Let A=\begin {pmatrix}1&0\\0&1 \end{pmatrix}

As A^2=A\times A=\begin {pmatrix}1&0\\0&1 \end{pmatrix}\begin {pmatrix}1&0\\0&1 \end{pmatrix}=\begin {pmatrix}1&0\\0&1 \end{pmatrix}=A, A is idempotent.

So, A \in H

A+A=\begin {pmatrix}1&0\\0&1 \end{pmatrix}+\begin {pmatrix}1&0\\0&1 \end{pmatrix}=\begin {pmatrix}2&0\\0&2\end{pmatrix} \\ \left ( A+A \right )^2=\begin {pmatrix}2&0\\0&2\end{pmatrix}\begin {pmatrix}2&0\\0&2\end{pmatrix}=\begin {pmatrix}4&0\\0&4\end{pmatrix}\neq ASo, A+A is not idempotent and hence, does not belong to H.

So, H is not a subspace of the vector space V.

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Step2247 [10]

Respuesta:

(2945.411; 3054.589)

Explicación paso a paso:

Dado ;

Tamaño de la muestra, n = 50

Media, xbar = 3000

Desviación estándar, s = 200

Nivel de confianza, Zcrítico al 95% = 1,96

El intervalo de confianza se define como:

Xbar ± margen de error

Margen de error = Zcrítico * s / sqrt (n)

Margen de error = 1,96 * 200 / sqrt (50)

Margen de error = 54.589

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3 years ago
The decibel level of sound is 50 dB greater on a busy street than in a quiet room where the intensity of sound is watt/m2. The l
makkiz [27]

Complete question is;

The decibel level of sound is 50 dB greater on a busy street than in a quiet room where the intensity of sound is 10^-10 watt/m2. The level of sound in the quiet room is (10,20,100) dB, and the intensity of sound in the busy street is (10^-1, 10^-5, 10^-10) watt/m2.

Use the formula , β = 10log I/I 0 where β is the sound level in decibels, I is the intensity of sound you are measuring, and Io is the smallest sound intensity that can be heard by the human ear (roughly equal to 1 x 10^-12 watts/m2).

Answer:

A) The level of sound in the quiet room will be 20 dB

B) The intensity of sound in the busy street is 10⁻⁵ W·m⁻²

Step-by-step explanation:

Formula given is; β = 10log(I/I₀)

(a) For Quiet room:

We are given;

I = 10⁻¹⁰ W·m⁻²

I₀ = 1 × 10⁻¹² W·m⁻²

Plugging these values into the given equation, we have;

β = 10log[(10⁻¹⁰/(1 × 10⁻¹²)]

β = 10log(10²)

β = 10 × 2 = 20 dB

Thus, the level of sound in the quiet room will be 20 dB.

(b) For the Street;

We are given;

β(street) - β(room) = 50 dB

Now, let's rewrite the given intensity level equation;

β = 10logI - 10 logI₀

Now, Let the intensity level for the room be β₁ and let the intensity level for the road be β₂. Thus;

β₁ = 10logI₁ - 10log I₀ - - - - (eq 1)

β₂ = 10logI₂ - 10logI₀ - - - - (eq 2)

Subtract eq 1 from eq 2 to give;

β₂ - β₁ = 10logI₂ - 10logI₁

50 = 10logI₂ - 10log(10⁻¹⁰)

Divide each term by 10 to give:

5 = logI₂ - log(10⁻¹⁰)

5 = logI₂ - (-10)

5 = logI₂ + 10

Subtract 10 from each side to give;

-5 = logI₂

Taking the antilog of both sides to give;

I₂ = 10⁻⁵ W·m⁻²

Thus, the intensity of sound in the busy street is 10⁻⁵ W·m⁻².

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Answer:

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where m is the slope and (a, b) a point on the line

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with slope m = - 10 → (1)

(a, b) = (3, - 6) → (4)


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Answer:

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Step-by-step explanation:

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Answer:

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