84................................
<span>-2×5+-8
We carry out the multiplication first.
-2 × 5 = -10
</span><span>-2×5+-8
= -10 + -8
+(-) = -
</span>
<span> -10 + -8 = -10 - 8 = - (10 + 8) = -18
I hope this helps.</span>
Quadrant 2 is where it would b
Answer:
The height of the plank after the π/3 rotation motion is 8.464 ft
Step-by-step explanation:
The radius of the wheel = 4 ft
The elevation of the bottom of the wheel from the bottom = 1 foot
The angle to which the wheel is rolled = π/3 radians
The height of a rotating wheel is given by the following relation
f(t) = A·sin(B·t + C) + D
Where;
D = Mid line = 4 + 1 = 5 feet
B·t = π/3
C = 0
A = The amplitude = 4
Which gives;
f(t) = 4×sin(π/3) + 5 = 8.464 ft
The height of the plank after the π/3 rotation motion = 8.464 ft.
