The accumulated (future) value is given by the formula
F=P(1+i)^n
where
P=amount of deposit (made at the beginning of the first period)
i=monthly interest, APR/12 = 3%/12 =0.0025
n=number of periods (month)
For example, the future value for the 6th month is
F(6)=1000(1.0025^6)=1015.09 (to the nearest cent)
Here is a schedule of the values,
i=month
F(i) = value at the end of month i.
i F(i)
0 1000.0
1 1002.5
2 1005.01
3 1007.52
4 1010.04
5 1012.56
6 1015.09
7 1017.63
8 1020.18
9 1022.73
10 1025.28
11 1027.85
12 1030.42 + $50 deposit = 1050.42
All values are rounded to the nearest cent.
Answer:
Do you mean strandord or expanded form?
Step-by-step explanation:
Answer:
The answer is p+q
Step-by-step explanation:
Answer:
You did not post the options, but i will try to answer this in a general way.
Because we have two solutions, i know that we are talking about quadratic equations, of the form of:
0 = a*x^2 + b*x + c.
There are two easy ways to see if the solutions of this equation are real or not.
1) look at the graph, if the graph touches the x-axis, then we have real solutions (if the graph does not touch the x-axis, we have complex solutions).
2) look at the determinant.
The determinant of a quadratic equation is:
D = b^2 - 4*a*c.
if D > 0, we have two real solutions.
if D = 0, we have one real solution (or two real solutions that are equal)
if D < 0, we have two complex solutions.
