Please answer the question in the photo that I have attatched. Please also explain how to solve it so I may solve the others.
1 answer:
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Answer:
The answer is: 3
Step-by-step explanation:
1. At the begining of the program we start by declairing the variables:
double x=1, double y=1 and int i=0.
2. The structure do...while is used to defined the loop. x<2.5 is the finalization condition of the loop. i is the counter of the loop.
y=x/2 is the first calculation
x=x+y is the second one. Here is where the values of the variable x changes.
a) for the first iteration, the values of y and x are shown below:
The variable x is minor to 2.5 so the loop will continue computing.
b) the second iteration, the values of y and x are shown below::
The variable x is still minor to 2.5 so the loop will continue computing.
c) third iteration:
The condition x<2.5 is not true so the loop ends.
3. System.out.print(i + " "); displays the value of the variable i wich value is 3.
Therefore the number 3 is display.
Answer:
The required expression is:
Option C is correct option.
Step-by-step explanation:
We need to find the equation that fits the description.
a) the expression is the quotient of two quantities
The quotient is expressed as
where a is numerator and b is denominator
b) The numerator of the expression is product of 5 and the sum of x and y
Sum of x and y = x+y
Product of 5 and Sum of x and y = 5(x+y)
So, Numerator of the expression is 5(x+y)
c) The denominator is the product of negative 8 and x
Product of negative 8 and x = -8x
So, denominator of the expression is -8x
Now, The required expression is:
Option C is correct option.