All categories

3 years ago

In circle C, SQ = 10 cm. Which statements about the circle are correct? Check all that apply.

Mathematics

1 answer:

lbvjy [14]3 years ago

4 0

Answer: A, B, D, E

Arc PQ is congruent to arc SR.

The measure of arc QR is 150°

Arc PS measures about 13.1 cm.

Arc QS measures about 15.7 cm.

Step-by-step explanation:

You might be interested in

Name:

ad-work [718]

Answer:a) 84π b) 109.2π

Step-by-step explanation:

The formula to find this is v=πr^2h/3

r=d/2. so the radius (r) is 6 because you have to divide the diameter (12) by 2. and the height is 7. so, 6^2=36 and 36x7=252.

252/3=84

and because the question is asking for the EXACT value, you need to just put the pi symbol next to it. Final answer for a is 84π

B) you need to find 30% of 84, which is 25.2 and add it to 84, and you will get 109.2! Final answer is 109.2π.

7 0

3 years ago

The combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 m

rewona [7]

Answer:

Approximately 50 pounds less carbon (in CO₂) will be produced by the second auto on this trip.

Step-by-step explanation:

We have been given that the combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 miles.

Let us find amount of fuel used by autos by dividing the total distance by their mileage.

$\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\frac{\text{ 20 miles}}{\text{gallon}}}$

$\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\text{ 20 miles}}\times \text{gallon}$

$\text{Fuel used by 1st auto}=30 \text{ gallons}$

$\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\frac{\text{ 30 miles}}{\text{gallon}}}$

$\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\text{ 30 miles}}\times \text{gallon}$

$\text{Fuel used by 2nd auto}=20 \text{ gallons}$

Let us find the difference of fuel used by both autos.

$\text{Number of gallons that 2nd auto used less than 1st auto}=30-20$

$\text{Number of gallons that 2nd auto used less than 1st auto}=10$

Since one gallon of automobile fuel produces about 5 pounds of carbon, so 10 gallons of fuel will produces $5\times 10=50$ pounds of carbon.

Since 2nd auto used 10 gallons less than 1st auto, therefore, 2nd auto will produce 50 pounds less carbon than 1st auto.

8 0

3 years ago

The length of a rectangle is 59 inches greater than twice the width. If the diagonal is 2 inches more than the length, find the

Paul [167]

So.. hmm notice the picture here

we know the length is 59 more than twice the width,
twice the width, 2 * w, or 2w
59 more than that
2w + 59

we also know that, whatever that is, the diagonal of it is,
2 more inches than that, or
(2w + 59) + 2

now.. use the pythagorean theorem
$\bf c^2=a^2+b^2\implies \qquad 
\begin{cases}
a=2w+59\\
b=w\\
c=(2w+59)+2\to 2w+61
\end{cases}
\\\\\\
(2w+61)^2=(2w+59)^2+(w)^2
\\ \qquad\qquad \uparrow\qquad \qquad\qquad \qquad \uparrow \\
\textit{expand using binomial theorem, or FOIL}$

you'd end up with a quadratic, after simplifying, solve for "w"

7 0

3 years ago

3. Find the least number which must be added to the following numbers to make them a perfect square. i) 37460 ii) 506900 iii) 49

EastWind [94]

Answer:

i). 211.

ii). 711.

iii). 31

iv). 131.

Step-by-step explanation:

i). √37460 = 193.545

Then take the whole number from the decimal:

193² = 193 × 193 = 37249

You subtract the answer from the main number:

37460 - 37249 = 211

211 is the answer.

ii). √506900 = 711.969

711² = 711 × 711 = 505521

506900 - 505521 = 1379

1379 is the answer.

iii). √4931 = 70.221

70² = 70 × 70 = 4900

4931 - 4900 = 31

31 is the answer.

iv). √5607 = 74.879

74² = 74 × 74 = 5476

5607 - 5476 = 131

131 is the answer.

Hope you understand ◉‿◉ (✷‿✷) (◠‿◕)

8 0

3 years ago

Will mark BRAINLIEST !!<br> Number 16. Help

Slav-nsk [51]

Answer:

can you show the other answers to see if I have the answer sorry.

6 0

3 years ago