Answer:
In the Sympathetic Nervous System PNS subdivision in which nerve injury would be the most dangerous for life.
Explanation:
In the Sympathetic Nervous System PNS subdivision in which nerve injury would be the most dangerous for life.
It is important for survival to fight or respond to flight because it controls the physiological reaction to a risk or danger and this flight and flight response is activated by sympathetic nervous system. This system is a part of automatic nervous system and operated by various interconnected neuron
I think it would be A. Because DNA always has your genes
Drosophila melanogaster an excellent model for studying fundamentals of development because many of the genes involved in the development of the fruit fly are also found in humans and the precise formation of each of their 959 body cells has been mapped.
Its many of the genes involved in the development of the fruit fly are also found in humans. Drosophila melanogasteris which is also called Fruit fly is small in size and minimal requirements, many fly's can be raised and tested within a small laboratory which does not have access time, space or funding.
Genetic factors also make this fly an ideal model organism. Drosophila melanogasteris only has four pairs of chromosomes compared to 23 pairs in humans.
To learn more about Drosophila melanogaster here
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Its .C It stores genetic information
Answer:
Yeah, so basically the image is showing restriction enzymes. The job of restriction enzymes is mainly involved in research when scientists use them for cloning human genes. But that's besides the point...
Main thing you have to understand is that restriction enzymes cut at very specific places along DNA sequences. If you look at the restriction enzyme Rsa 1, you can notice that it cuts only between a thymine nucleotide base and an adenine nucleotide base. Next, if ya look at Sty 1 (be careful b/c W can represent adenine or thymine), it cuts only between two directly adjacent cytosine nucleotide bases!
SO.... if we go to Rsa 1, we can find the answers by dividing up the sequences between the pattern we saw in the gray box. It only cuts between adenine and thymine bases. Based on that, we can find the number of fragments created, and the segment lengths (basically just like how many nucleotide bases are in each strand). Hope ya found this helpful!