Answer:
Brute Force attack.
Explanation:
A network is a platform where end user devices like computers are connected to communicate and share resources. There are public networks and private networks.
A public network has its end devices and servers configured with a public IP address, which is routable on the internet, while private networks uses private IP addresses which can be used on the internet.
Private networks can be made accessable to public users by configuring an authentication and authorization policy, which could be one or a multi factor authentication. These requires a password and other factors to access the services of a private network.
An attacker can easily access a one factor or a password accessible user account, if the password is weak by using the process called a brute Force attack.
The brute Force attack exploits the vulnerability of weak passwords by entering possible valid combination from a defined set of possibilities.
Abstraction make programming languages easier to use as It eliminates the need for codes to be automated.
<h3>How does abstraction make programming languages easier to implement?</h3>
Data abstraction is known to be a tool that helps a person to change a complex data structure into simple ones which can be used easily.
Note that Abstraction make programming languages easier to use as It eliminates the need for codes to be automated.
Learn more about abstraction from
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The loop terminates when "xxxxx" is read in. If the word is land, the string followed by "land" get outputted. The same with air, and water.
Explanation:
int land = 0;
int air = 0;
int water = 0;
String word = "";
while(!(word.equals("xxxxx"))) {
word = stdin.next();
if(word.equals("land")) {
land++;
}else if(word.equals("air")) {
air++;
}else if(word.equals("water")) {
water++;
}
}
System.out.println("land:" + land);
System.out.println("air:" + air);
System.out.println("water:" + water);
Explanation:
Explanation:
RSA encryption is performed by calculating C=M^e(mod n).
However, if n is much larger than e (as is the case here), and if the message is not too long (i.e. small M), then M^e(mod n) == M^e and therefore M can be found by calculating the e-th root of C.
