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3 years ago

____________ are collected from several entities at the same point in time.

Computers and Technology

1 answer:

allochka39001 [22]3 years ago

8 0

Answer:a) Cross-sectional data

Explanation: Cross -sectional data is the data/information that is based on the statistics and certain time instance.This data covers the particular time range that can be of a year, month , hour etc. for the several other components and then creates the statistic chart .

Other options are incorrect because they don't measure the data by observing it at the particular time instance/period.Thus the correct option is option(a).

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The best defenses against covert channels include IDS and intrusion prevention system (IPS) and thoroughly watching all aspects

ddd [48]

Answer:

The statement is True

Explanation:

When talking about computer security, we can define covert channels as an attack on a system capable of creating a loophole for information objects transfer between various processes that would normally not allow communication under the computer security policy. Hence, the best defenses system against this kind of attack is via Intrusion Defense System and Intrusion Prevention System and relentlessly "watching all aspects of an IT infrastructure for aberrant or abnormal events of any type."

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3 years ago

Which items make up the stamen of a flower? Stigma, style, filament, anther, ovule.

d1i1m1o1n [39]

Anther and Filament
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4 years ago

Write a Python 3 script in PyCharm that will simulate the game of "Rock, Paper, Scissors": Display a header and the simple rules

mr Goodwill [35]

Answer:

'''

Rock, Paper, Scissors:

The Rules:

If player1's move equivalent to player2's move, "It's a tie".

"rock" beats "scissors", "scissors" beats "paper", and "paper" beats "rock"

'''

player_1 = input("Player 1's move: ")

print('*** NO CHEATING ***' * 20)

player_2 = input("Player 2's move: ")

if player_1 or player_2 not in ["rock", "paper", "scissors"]:

print("Invalid input!")

if player_1 == player_2:

print("It's a tie")

else:

if player_1 == "rock":

if player_2 == "scissors":

print("Player 1 won")

elif player_2 == "paper":

print("Player 2 won")

elif player_1 == "scissors":

if player_2 == "paper":

print("Player 1 won")

elif player_2 == "rock":

print("Player 2 won")

elif player_1 == "paper":

if player_2 == "rock":

print("Player 1 won")

elif player_2 == "scissors":

print("Player 2 won")

Explanation:

In the comment part, put the header and the rules of the game

Ask the user to enter the player1's move

Print the asterisks

Ask the user to enter the player2's move

If any of the input is not "rock", "paper", "scissors", state that the input is invalid

Check the inputs. If they are equal, print that it is a tie. Otherwise:

If player1's move is rock. Check player2's move. If it is "scissors", player1 wins. If it is "paper", player2 wins

If player1's move is scissors. Check player2's move. If it is "paper", player1 wins. If it is "rock", player2 wins

If player1's move is paper. Check player2's move. If it is "rock", player1 wins. If it is "scissors", player2 wins

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3 years ago

Make up a python program that can do the following

GalinKa [24]

Answer:

hrs=input("Enter Hour:")

rate=input("Eenter Rate per Hour:")

pay=float(hrs)*float(rate)

print("Pay:", pay)

Explanation:

7 0

3 years ago

Write a C++ program to Calculate the value of π from the infinite series Print a table that shows the value of π approximated by

nata0808 [166]

The C++ program is an illustration of loops and conditional statements

<h3>How to analyze the infinite series</h3>

The infinite series is given as:

$\pi = 4 - \frac 43 + \frac 45 - \frac 47 + \frac 49 -\frac 4{11} + ....$

The above series shows that, the addition and the subtraction signs are interchanged, and the denominator of the fractions increase by 2 while the numerator remains the same

<h3>The main program</h3>

The program written in C++, where comments are used to explain each line is as follows:

#include <iostream>

using namespace std;

int main(){

//This initializes the value of pi to 0

double pi = 0;

//This iterates from 1 to 200000

for(int i = 0; i< 200000; i++){

//The following conditions determine the value of pi

if(i%2==0){

pi+=4.0/(1.0+2.0*i);

}

else{

pi-=4.0/(1.0+2.0*i);

}

//This prints the value of pi

cout<<pi;

return 0;

}

Read more about loops and conditional statements at:

brainly.com/question/24833629

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2 years ago