What can a parent do to help a child adjust to a new culture or area

What output is produced by

Natasha_Volkova [10]

Answer:

The answer to this question is given below in the explanation section. the correct option is C.

Explanation:

This is Java code statement:

System.out.print("Computing\nisInfun");

The output of this code statement is

Computing

isInfun

However, it is noted that the C option is not written correctly, but it is guessed that it will match to option C.

This Java code statement first prints "Computing" and then on the next line it will print "isInfun" because after the word "Computing" there is a line terminator i.e. \n. when \n will appear, the compiler prints the remaining text in the statement on the next line.

4 0

3 years ago

How would I copy this image?

Dahasolnce [82]

Question: How would I copy this image?

Answer: Either screenshot it, or CTRL C ± CTRL V it. To screenshot something, open 'snipping tool' and pull up the PDF, then box in whatever you are trying to copy. You can also reverse image search it to find it somewhere on the web.

Uplifting Note: To you, smiling at someone may mean nothing, but to them, it might be their whole world.

3 0

3 years ago

According to the information presented in this video, a spreadsheet is effective for managing information about one thing (e.g

Nat2105 [25]

Answer:

According to the information presented in this video, a spreadsheet is effective for managing information about one thing (e.g., items for sale), but a

C. database

is better for managing information about more than one thing (e.g., items for sale and suppliers of items).

Explanation:

The option A is not correct as the flowchart is a step-by-step explanation of a procedure. It is visual presentation in which we explain a whole process.
The option B is not correct as network is defined as the group of different computers, servers and other machines that helps the exchange of data.
The option c is correct as database is the means of storage of data as well as we can access this data at any time and it let you manage the data as well so we can manage a lot of information about multiple things at a time.
The option d is also incorrect as workflow is the visual presentation of sequence in which tasks are performed so it doesn't have to do anything wit the managing the information.
The option e is also incorrect as data model defines the properties of data of different things and it is used in database. It sets the rule of storing, managing and accessing the data in a database.

7 0

3 years ago

In which conditions, a trial balance does not tally?

Nostrana [21]

Answer:

A trial balance will not balance if both sides do not equal, and the reason has to be explored and corrected.

Explanation:

The debit side and the credit side must balance, meaning the value of the debits should equal the value of the credit

4 0

3 years ago

find_cow(name, cows) Given a name and a Python list of Cow objects, return the Cow object with the specified name. If no such Co

nadya68 [22]

Using the computational knowledge in python it is possible to write a code that Given a name and a Python list of Cow objects

<h3>Writting the code in python:</h3>

def load_cows(filename):

cow_dict = dict()

f = open(filename, 'r')

for line in f:

line_data = line.split(',')

cow_dict[line_data[0]] = int(line_data[1])

return cow_dict

def greedy_cow_transport(cows, limit=10):

trips = []

cowsCopy = cows.copy()

sortedCows = sorted(cowsCopy.items(), key=lambda x: x[1], reverse = True)

while sum(cowsCopy.values()) > 0:

ship = []

total = 0

for cow, value in sortedCows:

if cowsCopy[cow] != 0 and value + total <= limit:

ship.append(cow)

total += value

cowsCopy[cow] = 0

trips.append(ship)

return trips

def brute_force_cow_transport(cows,limit=10):

trips = []

possibilities = []

for i in power_list:

ship = []

for j in i:

ship_weights = []

for k in j:

ship_weights.append(cows[k])

#print(ship_weights)

ship.append(sum(ship_weights))

#print(ship)

if all(d <= limit for d in ship):

possibilities.append(i)

pruned_possibilities = []

for k in possibilities:

if k not in pruned_possibilities:

pruned_possibilities.append(k)

# now find the minimum list length:

min_list_len = min(map(len, pruned_possibilities))

for l in pruned_possibilities:

if len(l) == min_list_len:

return l

def compare_cow_transport_algorithms():

greedy_start = time.time()

greedy_results = greedy_cow_transport(cows, limit = 10)

greedy_end = time.time()

print('Greedy Algorithm time:', greedy_end -greedy_start)

brute_force_start = time.time()

brute_force_results = brute_force_cow_transport(cows, limit = 10)

brute_force_end = time.time()

print('Brute force time:', brute_force_end - brute_force_start)

print('Greedy Algorithm results:', greedy_results)

print('Number of trips returned by Greedy Algorithm:', len(greedy_results))

print('Brute Force Algorithm results:', brute_force_results)

print('Number of trips returned by Brute Force Algorithm:', len(brute_force_results))

See more about python at brainly.com/question/13437928

#SPJ1

4 0

2 years ago