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dimaraw [331]
3 years ago
6

in a class of 25 students 8% of the students play on a softball team how many students play on the softball team

Mathematics
1 answer:
Alla [95]3 years ago
8 0

2 students play on the softball team

<u>Solution:</u>

Given that in a class of 25 students, 8 % of students play on a softball team

To find: Number of students play on softball team

Total number of students in class = 25

8 % of students play on a softball team means that 8 % of total students play on softball team

Therefore, number of students play on softball team is given as:

\rightarrow 8 \% \text{ of } 25\\\\\rightarrow 8 \% \times 25\\\\\rightarrow \frac{8}{100} \times 25\\\\\rightarrow \frac{8}{4} = 2

Thus 2 students play on the softball team

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A restaurant offers three types of meats: chicken, beef,
sp2606 [1]

Answer:

200

Step-by-step explanation:

If the waiters surveyed 50 customers and half of the customer's favorite meat was chicken, then if 400 pieces of meat were ordered 200 pieces should be chicken.

If \frac{50}{chicken} = \frac{50}{25} = \frac{1}{2}, then \frac{400}{chicken} = \frac{400}{2} = 2

I hope that makes sense :)

7 0
3 years ago
(1) In Section 1.4 we used the Axiom of Completeness (AoC) to prove the Archimedean Property of R (Theorem 1.4.2). Show that the
serious [3.7K]

Answer:

Both Answers are in the following attachment (a) and (b)

Step-by-step explanation:

3 0
3 years ago
The admission fee at an amusement park is 20$ for children and 35$ adults. On a certain, day 264 people entered the park, and th
shtirl [24]

Answer:

100 Adults and 164 Children

Step-by-step explanation:

To solve this we will need to write two equations to solve for the two unknowns. Firstly, we know that tickets are 20 for children and 35 for adults, and that the total price was 6780. We can write an expression to represent this. 6780 is the total price, this also means it is the price of all the adults + the price of all the children. The total price of the adults tickets is the price of each ticket multiplied by the number of adults, so the total price of adult tickets can be represented by: 35A, 35 being the ticket price per adult, and A being the number of adults. Similarly the total children's price can be expressed as such: 20C, 20 being the price per child, and C being the number of children. Since we know that these two values total to 6780, we can now form an equation:

35A (total adult price) + 20C (total children price) = 6780

35A+20C=6780

Now we need another expression so we can substitute for one of the values. The other piece of information we are given, is that a total of 264 people entered the park. This means that the total number of adults + the total number of children = 264. Since we already have variables for the numbers of adults and children we now have our second equation:

A (number of adults) + C (number of children) = 264

A+C=264

Now we can use this second equation to substitute for one of the values in the first equation. Let's substitute for children:

If we rearrange the second expression we will get:

A+C-A=264-A

C=264-A

So now we substitute this expression into our first formula:

35A+20C=6780

C=264-A

35A+20(264-A)=6780

Now since we only have one unknown, we can simplify, expand and solve!

35A+20*264-20*A=6780

35A+5280-20A=6780

35A-20A+5280-5280=6780-5280

15A=1500

15A/15=1500/15

A= 100

A total of 100 adults were admitted.

Now we can use the number of adults to find the number of children using our second formula:

C=264-A

C=264-100

C=164

And there we are! A total of 100 adults and 164 children were admitted.

Hope this helped!

4 0
4 years ago
D -e/3d + e= e, for d​
navik [9.2K]

Answer:

\large\boxed{d=\dfrac{e^2+e}{1-3e}}

Step-by-step explanation:

\dfrac{d-e}{3d+e}=e\\\\\dfrac{d-e}{3d+e}=\dfrac{e}{1}\qquad\text{cross multiply}\\\\(1)(d-e)=(e)(3d+e)\qquad\text{use the distributive property}\\\\d-e=3de+e^2\qquad\text{add}\ e\ \text{to both sides}\\\\d=3de+e+e^2\qquad\text{subtract}\ 3de\ \text{from both sides}\\\\d-3de=e^2+e\qquad\text{distribute}\\\\d(1-3e)=e^2+e\qquad\text{divide both sides by}\ (1-3e)\\\\d=\dfrac{e^2+e}{1-3e}

8 0
3 years ago
A house costs 36% more today than when it was built.If the cost of the house today is $333,200, find the cost when it was built.
LenKa [72]

Answer:

$245,000

Step-by-step explanation:

Let the intial cost = x

100\% + 36\% = 136\% = 1.36

1.36x = 333200

x =  \frac{333200}{1.36}

x = 245000

3 0
2 years ago
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