All categories

3 years ago

in a class of 25 students 8% of the students play on a softball team how many students play on the softball team

Mathematics

1 answer:

Alla [95]3 years ago

8 0

2 students play on the softball team

Solution:

Given that in a class of 25 students, 8 % of students play on a softball team

To find: Number of students play on softball team

Total number of students in class = 25

8 % of students play on a softball team means that 8 % of total students play on softball team

Therefore, number of students play on softball team is given as:

$\rightarrow 8 \% \text{ of } 25\\\\\rightarrow 8 \% \times 25\\\\\rightarrow \frac{8}{100} \times 25\\\\\rightarrow \frac{8}{4} = 2$

Thus 2 students play on the softball team

You might be interested in

What is the slope of a line that is parallel to the line represented by the equation y=7/6x+4

Alekssandra [29.7K]

7/6
The slope of the equation in the form y=Mx+c is m
Parallel lines have Same gradient
Which makes gradient 7/6

Please mark as brainliest

4 0

3 years ago

Which situation shows a constant rate of change?

kolbaska11 [484]

The answer is most likely B. :)

3 0

2 years ago

PLEASE HELP WITH EXPLAINING I WILL MARK BRAINIES!!!

Drupady [299]

Answer: 3 mph

Step-by-step explanation:

1. 1/2 mph for 1/2 an hour as they said, meaning that they would've walked for 3 miles kn an hour.

2. 4 and 1/2 miles.

3 + 1 2/4. = 4 1/2

3. 1 3/4 hours.

3 + 2.25 = 5.25

3 x .75 = 2.25

3 miles per hour.

8 0

3 years ago

Please help with this Math Question...

Nataly [62]

Answer: A

Step-by-step explanation:

f(x) = x³ + 4x² + 7x + 6

possible rational roots are ±{1, 2, 3, 6}

Try x = -2

-2 | 1 4 7 6

| ↓ -2 -4 -6

1 2 3 0 ← remainder is 0 so x = -2 is a root ⇒ (x + 2) = 0

The factored polynomial x² + 2x + 3 = 0 is not factorable so use the quadratic formula to find the roots.

a=1, b=2, c=3

$x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}$

$x=\dfrac{-(2)\pm\sqrt{(2)^2-4(1)(3)} }{2(1)}$

$x=\dfrac{-2\pm\sqrt{4-12} }{2}$

$x=\dfrac{-2\pm\sqrt{-8} }{2}$

$x=\dfrac{-2\pm2i\sqrt{2}}{2}$

$x = -1 \pm i\sqrt{2}$

$x = -1 + i\sqrt{2}$ $x = -1 - i\sqrt{2}$

$x - (-1 + i\sqrt{2})=0$ $x - (-1 - i\sqrt{2})=0$

The factors are:

$(x - 2)[x - (-1 + i\sqrt{2})][x - (-1 - i\sqrt{2})]$

5 0

3 years ago

Which method would you use to prove that the two triangles are congruent?

tankabanditka [31]

You can use the SSS, SAS, ASA, AAS congruency for any triangles and the HL congruency for just the right triangle

4 0

4 years ago