Answer: D. Maintaining the same width of the compass as AB, draw an arc from point X such that it intersects the arc drawn from N in a point Y.
Took the test.
Answer:
jvjjvscsjcsjsvjscjsvhchhcuhcjwcwh ejcisvsufjdtsydghcwhcjwvhsvjscekfdjsvjsfjsvkdvs
Step-by-step explanation:
30y
Answer:
6.9 6.9 6.9 6.9 6.9 6.9 6.9 6.9 6.9
Cost per meter(C) = $60/m
Length of rectangular field(L) = 50m
L = 2W
-> W = L/2
-> W = 50/2
-> Width of rectangular field = 25m
Cost of one field length(l) = L x C
-> l = 50 x 60
-> l = $3000
Two of the lengths of the field = 2 x l
-> 2 x $3000
-> $6000
Cost of one field width(w) = W x C
-> w = 25 x 60
-> w = $1500
Two of the widths of the field = 2 x w
-> 2 x $1500
-> $3000
Cost of fencing entire field = $6000+$3000
Hence, total field cost = $9000