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3 years ago

9

Please answer the image below .

2 answers:

mojhsa [17]3 years ago

8 0

There u just needed to search the formula

Stolb23 [73]3 years ago

6 0

Answer:

<h2>7</h2><h2 />

Step-by-step explanation:

surface area of a square pyramid

= Area of base + 1/2 base perimeter * slant height

= (1 x 1) + (1/2 x (1*4) x 3)

= 1 + 6

= 7 yd²

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Yuki888 [10]

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That's not a subtractive equation, the symbol that you used indicates that it is an addition equation. if the question was 1-1 then the answer wouldn't be 2 but since the question is 1+1 the answer is 2

Step-by-step explanation:

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2 years ago

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2 years ago

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Kamila [148]

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84 meters

Step-by-step explanation:

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3 0

3 years ago

Solve the inequality:<br><br> 5x - 7 ≥ 3x + 9

erastova [34]

Answer:

x≥8

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Let $f(x) = 2x^2 + 3x - 9,$ $g(x) = 5x + 11,$ and $h(x) = -3x^2 + 1.$ Find $f(x) - g(x) + h(x).$

Viefleur [7K]

QUESTION 1

Given that:

$f(x)=2x^2+3x-9$ ,

$g(x)=5x+11$ ,

and

$h(x)=-3x^2+1$

Then;

$f(x)-g(x)+h(x)=2x^2+3x-9-(5x+11)+(-3x^2+1)$

$f(x)-g(x)+h(x)=2x^2+3x-9-5x-11-3x^2+1$

Group similar terms;

$f(x)-g(x)+h(x)=2x^2-3x^2+3x-5x-11-9+1$

Simplify;

$f(x)-g(x)+h(x)=-x^2-2x-19$

QUESTION 2

Given that;

$f(x)=4x-7$ .

$g(x)=(x+1)^2$

and

$s(x)=f(x)+g(x)$

Substitute the functions;

$s(x)=4x-7+(x+1)^2$

Substitute x=3

$s(3)=4(3)-7+(3+1)^2$

$s(3)=12-7+(4)^2$

$s(3)=5+16$

$s(3)=21$

QUESTION 3

Given:

$f(x)=3x+2$

$g(x)=x^2-5x-1$

$f(g(x))=f(x^2-5x-1)$

This implies that;

$f(g(x))=3(x^2-5x-1)+2$

Expand the parenthesis;

$f(g(x))=3x^2-15x-3+2$

$f(g(x))=3x^2-15x-1$

QUESTION 4

The given function is;

$f(x)=3(x-6)^2+1$

Let

$y=3(x-6)^2+1$

$\Rightarrow y-1=3(x-6)^2$

$\Rightarrow \frac{y-1}{3}=(x-6)^2$

$\Rightarrow \sqrt{\frac{y-1}{3}}=x-6$

$\Rightarrow x=6+\sqrt{\frac{y-1}{3}}$

The range is:

$\frac{y-1}{3}\ge0$

$y-1\ge0$

$y\ge1$

The interval notation is;

$[1,+\infty)$

6 0

3 years ago