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professor190 [17]
3 years ago
12

Sketch the graph of the given function. Then state the function’s domain and range. f(x)= 1/2(5)^x+3

Mathematics
1 answer:
balandron [24]3 years ago
8 0

Answer:

Graph of the following function is attached with the answer.

Domain : ( - ∞ , + ∞ )

Range : ( 3 , + ∞ )

Step-by-step explanation:

f(x)=\frac{1}{2}x^{2}+3

Domain of any quadratic equation is from negative infinity to positive infinity under no restrictions.

So, Domain : ( - ∞ , + ∞ )

The Range of any function can be calculated easily if there is just one term with variable. The method to find Range by that method is explained with the example as follows:

  1. Range of x : ( - ∞ , + ∞ )
  2. Range of \textrm{x}^{2} : [ 0 , + ∞ ) as every square number is more than or equal to zero.
  3. Range of \frac{1}{2}\textrm{x}^{2} : [ 0 , + ∞ ) as 0/2 = 0 and ∞/2 = ∞.
  4. Range of \frac{1}{2}\textrm{x}^{2}+3 : [ 3 , + ∞ ) as 0 + 3 = 3 and ∞ + 3 = ∞.

Therefore the Range of \mathbf{f(x)\boldsymbol=\frac{1}{2}x^{2}\boldsymbol+3} is [ 3 , + ∞ )

(NOTE <em>: [a,b] means all the numbers between 'a' and 'b' including 'a' and 'b'.</em>

<em>(a,b) means all the numbers between 'a' and 'b' excluding 'a' and 'b'.</em>

<em>(a,b] means all the numbers between 'a' and 'b' including only 'b' not 'a'.</em>

<em>[a,b) means all the numbers between 'a' and 'b' including only 'a' not 'b'.</em>

<em>{a,b} means only 'a' and 'b'.</em>

<em>{a,b] or (a,b} doesn't mean anything.</em> )

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An object has been thrown straight up into the air. The formula h = vt - 16t^2 gives the height of the object above the ground a
Oxana [17]

Answer:

8 seconds.

Step-by-step explanation:

To solve this question, we need to find the time, t, when h = 0, that is, when the height of the object above the ground is 0 feet.

Substituting v = 128 feet per second and h = 0 gives  the quadratic:

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We can easily see that one answer to the equation is 0,

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6 0
3 years ago
CAN U GUYS PELASE ANSWER THE SIMULTANEOUS EQUATION QUESTION QUESTIONS ASAP. THIS IS EXTREMELY URGENT. Solve it by using the subs
prisoha [69]

Answer:

a ) y = 1 and x = -1

d) y = 5 and x = -1/2

Step-by-step explanation:

<h2><u>Substitution method</u></h2><h2><u>Question a</u></h2>

y = x+ 2

y = 2x + 3

<em>we can make the first formula in terms of x , so we can place in into the second formula</em>

y = x + 2

x = y -  2

now put y - 2 where x is in the second equation

y = 2x + 3

y = 2(y - 2) + 3

y = 2y - 4 +3

now solve

4 - 3 = 2y -y

y = 1

since y = 1 we can find what x is by putting into the first formula

y = x +2

x = y - 2

x = (1) -2

x = -1

<h3><u>hence y = 1 and x = -1 </u></h3><h3><u /></h3><h2><u>Question d</u></h2>

y = 2x + 6

y = 4 - 2x

<em>we can make the first formula in terms of x , so we can place in into the second formula</em>

y = 2x + 6

y - 6 = 2x

x = (y-6)/ 2

now place (y-6)/2 where x is in the second formula

y = 4 -2x

y = 4 - 2 (\frac{y - 6}{2})

now solve

the multiplication by 2 and division by 2 are cancelled out

hence making the simplified equation as:

y = 4 - y + 6

2y = 4 + 6

2y = 10

y = 5

now place this into the first equation

y = 2x + 6

y - 6 = 2x

x = (y-6)/ 2

x = (5-6)/2

x = -1/2

<h3><u>hence y = 5 and x = -1/2</u></h3>

6 0
4 years ago
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valentinak56 [21]

9514 1404 393

Answer:

  (c)  (0, 6)

Step-by-step explanation:

Conventionally, an "ordered pair" is a pair of items in parentheses, separated by a comma. The items don't have to be numbers. (0, 6) is an ordered pair.

__

<em>Comments on the other answer choices</em>

Curly braces are usually used as delimiters of a set, not an ordered pair.

Three items do not constitute a "pair." Rather, they are a "triple."

Items without any particular indicator of grouping are usually not considered a "pair."

7 0
3 years ago
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