Question

Write the EQ of circle i find center and radius given x² + y²-4x+12y =-4

Answer 1

Answer:

CENTER :(2,-6)

RADIUS: 6

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Answer 2

Step-by-step explanation:

Hey there!

Given;

${x}^{2} + {y}^{2} - 4x + 12y = \: - 4$

Now, Try to make it a perfect square.

${x}^{2} - 4x + {(2)}^{2} - ( { 2)}^{2} + {y}^{2} + 12y + ( {6)}^{2} - ( {6)}^{2} = - 4$

Make perfect square and shift -(2)^2 and -(6)^2 on right side.

$( {x - 2)}^{2} ( {y + 6)}^{2} = - 4 + 40$

$( {x - 2)}^{2} ( {y + 6)}^{2} = 36$

Comparing the equation with (x-h)^2(y-h)^2= r^2.

We get,

Centre (h,k)= (2,-6)

Radius (r) = 6

Hope it helps...