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2 years ago

How many triangles can be made from the following three lengths: 3.1 centimeters, 9.8 centimeters, and 5.2 centimeters?

Mathematics

1 answer:

GenaCL600 [577]2 years ago

6 0

Answer:

none

Step-by-step explanation:

We have three sides

Adding the two smallest sides together must be bigger than the third side

3.1+5.2 > 9.8

8.3> 9.8

This is false, so we cannot make a triangle

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The bill at a restaurant came to $136.40. The patrons decided to leave a 15% tip. What was the total bill including the tip?

katen-ka-za [31]

Answer:

156.86

Step-by-step explanation:

The tip of fifteen percent will be $20.46

The total will be $156.86

6 0

2 years ago

A man bought 250 electric lanterns in the united States of America for $5000. he sold them them in lagos at 1,920 naira each. at

Maurinko [17]

Answer: 4166.67$

Step-by-step explanation:

1920 x 250 = amount

Amount = 120%

Cost price = 100%

1920 x 250= 120%

Cost price = 100%

Cross multiply and divide both side by 120

1920 x 250 x 100/120 = price

Exchange rate = cost in #/cost in $

= (1920 x 250 x 5/6)/(5000)

= (96 x 5/6) = 16 x 5= 80

Exchange rate then was 80 to 1$

The sales will be 400000/96 = 4166.67$

7 0

2 years ago

Read 2 more answers

Onesimus bought a phone for $ 75 and signed up for a single-line phone plan with 2000 monthly anytime minutes. The cost of the p

AysviL [449]

Answer:

cost for 21 months without considering cost of phone is $2,611.56

Total cost inclusive of cost of phone = $2,686.56

Step-by-step explanation:

cost of 2000 monthly anytime minutes plan = $ 124.36

So , in 1 month cost for given plan = $ 124.36

we have to find cost for 21 month

In 21 month, cost for given plan = 21 * cost of 1 month plan

In 21 month, cost for given plan = 21 * $ 124.36 = $2,611.56

cost for 21 months is $2,611.56.

Note, this cost is without considering the cost of phone as it is not mentioned cost of phone is to be included or not.

In case cost of phone is included then

Total cost inclusive of cost of phone = $2,611.56 + $75 = $2,686.56

7 0

3 years ago

Calculate the number of kilograms of mercury required to fill a pool that is 20.0 m x 50.0 m x 10.0 m. The density of mercury is

malfutka [58]

Answer:

$m=135000000 Kg$

Step-by-step explanation:

To find the number of kilograms of mercury we need to find how to relate density, mass and, volume. For this we shall recall the density formula:

$\rho=\frac{m}{V}$

where $\rho$ is the density, $m$ is the mass and, $V$ is the volume.

We have the density and want to compute the mass so now we want to know the volume of the pool.

The volume of a rectangular pool is given by the fomula:

$V= (length)(heigh)(width)$ .

So for our pool

$V= (20)(50)(10)$ .

$V= 10000m^{3}$ .

Our density is in $g/mL$ , so the last thing we need to do before computing the mass is to express the density in $Kg/m^{3}$ (this is because we want our mass in $Kg$ and, we have our volume in $m^{3}$ ).

For the density conversion we have to remember that

$1000mL = 1L$

$1L=0.001m^{3}$

$1000g=1Kg$

$\rho=13.5\frac{g}{mL}*\frac{1000mL}{1L}*\frac{1L}{0.001m^{3}}*\frac{1Kg}{1000g} =13500\frac{Kg}{m^{3}}$ .

With this we can finally compute mass:

$\rho=\frac{m}{V}$

$m=\rho*V$

$m=(13500*10000) Kg$

$m=135000000 Kg$ .

4 0

3 years ago

Please halp :D

madreJ [45]

She brought 2v and 2k that equal 100 even

8 0

2 years ago