You know that the discrete metric only takes values of 1 and 0. Now suppose it comes from some norm ||.||. Then for any α in the underlying field of your vector space and x,y∈X, you must have that
∥α(x−y)∥=|α|∥x−y∥.
But now ||x−y|| is a fixed number and I can make α arbitrarily large and consequently the discrete metric does not come from any norm on X.
Step-by-step explanation:
hope this helps
Answer:
100 bags
Step-by-step explanation:
S.E = σ/ √n
0.1 = 1 / √n
Square both sides
0.1² = 1² / n
0.01 = 1 / n
0.01n = 1
n = 1 / 0.01
n = 100
Answer: D. -30
Step-by-step explanation: EDGE 2022 I GOT 100%
Answer:
a- defined term
Step-by-step explanation:
The statement is defining an angle.
