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Dima020 [189]
3 years ago
11

Ants have 6 legs. Elena and Andre write equations showing the proportional relationship between the number of ants, a, to the nu

mber of ant legs, v. Elena writes a = 6 times v and Andre writes v =1/6 times a. Do you agree with either of the equations? Explain your reasoning.
Mathematics
1 answer:
Vlad [161]3 years ago
8 0

Answer:

I agree with Elena

Step-by-step explanation:

Ants have 6 legs. Elena and Andre write equations showing the proportional relationship between the number of ants, a, to the number of ant legs, v.

Elena writes a = 6 times v

Andre writes v =1/6 times a.

Mathematically

The number of ants a is directly proportional to the number of legs

=a ∝ v

Because if

1 ant = 6 legs

2 ants = x legs

x = 6 legs × 2

x = 12 legs

The number of ants is directly proportional to the number of legs

Therefore, Elena is correct and Andre is wrong.

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Step-by-step explanation:

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3 years ago
Determine the equation of the graph and select the correct answer (-4,-1)
Snowcat [4.5K]

Answer:

(-4,-1)

Step-by-step explanation:

Assuming the graph is the one shown in the attachment.

The forward sloping line has a slope of 1 and a y-intercept of 3.

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The horizontal line has a slope of 0 and y-intercept of -1.

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The two lines intersect at (-4,-1)

4 0
2 years ago
PLEASE HELP!! I WILL GIVE BRAINLIEST
sattari [20]

Answer: (a) The rate that the point 8,28 represents is 3.5 cm/s since 28/8 = 3.5  

(b) The unit rate is 3.5 cm/s since the rate is constant.

(c) The two points lie on the same line and that both points results to a rate of 3.5 cm/s.

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Write the slope-intercept form of the question of the line through the given point with the given slope.
Alexxx [7]

Answer:

y=x

Step-by-step explanation:

Slope intercept form of a line

y = mx+b

m is the slope

y = 1x+b

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8 0
3 years ago
A jogger runs 6 miles per hour faster downhill than uphill. If the jogger can run 5 miles downhill in the same time that it take
muminat

Answer:

The speed of jogger in uphills is 4 mile per hour  

And  The speed of jogger in downhills is 10 mile per hour

Step-by-step explanation:

Given as :

The distance cover by jogger in downhill (Dd) = 5 miles

The distance cover by jogger in uphill     (Du)  = 2 miles

The time taken by jogger in downhill       (Td)  = T  hour

The time taken by jogger in uphill            (Tu)  = T hour

Let The speed of jogger in uphills            (Su)  = x mph

So ,The speed of jogger in downhills      (Sd)  =( x + 6 ) mph

∵, Time = \frac{Distance}{Speed}

So, Tu = \frac{Du}{Su}

Or, T = \frac{2}{x}   h

And Td = \frac{Dd}{Sd}

Or,   T = \frac{5}{(x + 6)}  h

∵  Time duration of both is same

∴  \frac{2}{x} = \frac{5}{(x + 6)}

Or,  2 × (x + 6) = 5x

Or,  2x + 12 = 5x

So,    12 = 3x

∴       x = \frac{12}{3} = 4 mph

And  x + 6 = 4 + 6 = 10 mph

Hence The speed of jogger in uphills is 4 mile per hour  

And      The speed of jogger in downhills is 10 mile per hour   Answer

5 0
3 years ago
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