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Allushta [10]
3 years ago
11

3=4×3/4 what is true about this equation

Mathematics
1 answer:
Evgen [1.6K]3 years ago
6 0
It is true that 3=4 times 3\4 because 4 times 3 equals 12 while 12 divided by 4 equals 3.

3=3 is true.
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Goshia [24]
2p+3>2p-6
-3 -3
2p > 2p -8
0p >-8
C. No solution
6 0
3 years ago
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Correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.
klasskru [66]
F(x)=25-x^2
g(x)=x+5

f/g(x)=(25-x^2)/(x+5)

f(x) is in binomial form so 25-x^2 can also be written as (5-x)(5+x)

so

f/g(x)=(5-x)(5+x)/(x+5)
f/g(x)=5-x
5 0
3 years ago
A triangle has an angle that measures 55°. The other two angles are in a ratio of 11:14. What are the measures of those two angl
koban [17]

9514 1404 393

Answer:

  55° : 70°

Step-by-step explanation:

The sum of the two other angles is ...

  180° -55° = 125°

The sum of the ratio units is 11+14 = 25. Each ratio unit stands for 125°/25 = 5°. Then the other two angles are ...

  11×5° = 55°

  14×5° = 70°

8 0
3 years ago
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A gym has 200 members who pay $30 per month for unlimited use of the gym’s equipment. A survey of the members indicates that for
Bas_tet [7]
Given:

Current revenue = $6000

<span>R(f)= -100f^2 + 400f + 6000
where f is a whole number of $5 fee increases

We are told to find f, when R(f) </span><span>< 6000

Since </span>R(f)= -100f^2+400f+6000

R(f) < 6000 ⇒ -100f^2+400f+6000 < 6000


Subtract 6000 from both sides

-100f^2 + 400f + 6000 - 6000 < 6000 - 6000

-100f^2 + 400f < 0

⇒ 400f - 100f^2 < 0


Divide the equation by 100

400f/100 - 100f^2/100 < 0/100

4f - f^2 < 0


Add f^2 to both sides of the equation

4f - f^2 + f^2 < 0 + f^2

4f < f^2


Divide both sides by f

4f/f < (f^2)/f

4 < f

⇒ f > 4

⇒ f ≥ 5

Therefore, <span> for 5 or more numbers of $5 fee increases, the revenue from fees will actually be less than its current value.</span>
8 0
3 years ago
How much can 23 go into 162?​
Aneli [31]
23 can go 7 times into 162! Hope this helps ;(
5 0
3 years ago
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