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telo118 [61]
3 years ago
10

Rob collects data about how many customers

Mathematics
2 answers:
alexira [117]3 years ago
4 0
What is the question idk the question to answer
Brut [27]3 years ago
4 0
What's the question
You might be interested in
Please help out :)) and give a explanation
wolverine [178]

9514 1404 393

Answer:

  y = 3x

Step-by-step explanation:

A proportional relation has the equation ...

  y = kx

To write the desired equation, you need to know the value of k. That can be found from the given information:

  for x = 2, y = 6

  6 = k·2

  3 = k . . . . divide by 2

Now, we know the equation can be written ...

  y = 3x

5 0
2 years ago
Answer the question below
Lina20 [59]

Answer:

kckgkfjjfufufuf8f8ff88r8r8r8r8r8rrffufuufuff

3 0
3 years ago
What is 54 3/11 as a decimal
saul85 [17]
The answer is 54.27. Hope I was halpful 
8 0
2 years ago
If you need $8000 to travel to Europe after you graduate in 4 year. How much would your monthly deposits need to be if your acco
lina2011 [118]
\bf \qquad \qquad \textit{Future Value of an ordinary annuity}\\
\left. \qquad \qquad \right.(\textit{payments at the end of the period})
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]

\bf \qquad 
\begin{cases}
A=
\begin{array}{llll}
\textit{accumulated amount}\\
\end{array}\to &
\begin{array}{llll}
8000
\end{array}\\
pymnt=\textit{periodic payments}\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12\\
t=years\to &4
\end{cases}

\bf 8000=pymnt\left[ \cfrac{\left( 1+\frac{0.05}{12} \right)^{12\cdot 4}-1}{\frac{0.05}{12}} \right]
\\\\\\
\cfrac{8000}{\left[ \frac{\left( 1+\frac{0.05}{12} \right)^{12\cdot 4}-1}{\frac{0.05}{12}} \right]}=pymnt\implies \cfrac{8000}{\frac{\left( \frac{241}{240} \right)^{48}-1}{\frac{1}{240}}}=pymnt
\\\\\\
\cfrac{8000}{53.0148852}\approx pymnt\implies 150.9010152318\approx pymnt
6 0
3 years ago
Independent practice question 8=-12+5y
kodGreya [7K]
Y= 4

Have a great day :)
7 0
3 years ago
Read 2 more answers
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