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aksik [14]
1 year ago
7

A locker combination consists of two non-zero digits. the digits in a combination are not repeated and range from 2 through 9. e

vent a = the first digit is less than 5 event b = the second digit is less than 5 if a combination is picked at random, with each possible locker combination being equally likely, what is p(b|a) expressed in simplest form?
Mathematics
1 answer:
kolbaska11 [484]1 year ago
6 0

Answer:

1/3.

Step-by-step explanation:

P(event a occurs) = 3/9 = 1/3

P(event b occurs) = 3/9 = 1/3

P(a) ∩ P(b) = 1/3 * 1/3 = 1/9

P(b|a) = P(a) ∩ P(b) / P(a)

          =  1/9 / 1/3

          =  1/3.

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Find the mass at time t=0. ANSWER HAS TO BE IN GRAMS
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For part (a) the answer is 400 grams for part (b) 198.63 grams and for part (c)  20 years.

<h3>What is exponential decay?</h3>

During exponential decay, a quantity falls slowly at first before rapidly decreasing. The exponential decay formula is used to calculate population decline and can also be used to calculate half-life.

We have an equation for radioactive decay:

\rm m(t) = 400e^{-0.035t}

a) Plug t = 0

\rm m(0) = 400e^{-0.035\times 0}

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b) plug t = 20 years

\rm m(20) = 400e^{-0.035\times 20}

After solving:

m(20) = 198.63 grams

c) Plug m(t) = m(0)/2 = 400/2 = 200 grams

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x = 19.80 years ≈ 20 years

Thus, for part (a) the answer is 400 grams for part (b) 198.63 grams and for part (c)  20 years.

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3 0
2 years ago
If the sum of a number and 4 are doubled the result is two less than the number what's the number
Sedbober [7]
The number is -2

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3 years ago
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alexandr1967 [171]

By using parallel lines and transversal lines concept we can prove m∠1=m∠5.

Given that, a║b and both the lines are intersected by transversal t.

We need to prove that m∠1=m∠5.

<h3>What is a transversal?</h3>

In geometry, a transversal is a line that passes through two lines in the same plane at two distinct points.

m∠1+m∠3= 180° (Linear Pair Theorem)

m∠5+m∠6=180° (Linear Pair Theorem)

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Hence, proved. By using parallel lines and transversal lines concept we can prove m∠1=m∠5.

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