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aksik [14]
2 years ago
7

A locker combination consists of two non-zero digits. the digits in a combination are not repeated and range from 2 through 9. e

vent a = the first digit is less than 5 event b = the second digit is less than 5 if a combination is picked at random, with each possible locker combination being equally likely, what is p(b|a) expressed in simplest form?
Mathematics
1 answer:
kolbaska11 [484]2 years ago
6 0

Answer:

1/3.

Step-by-step explanation:

P(event a occurs) = 3/9 = 1/3

P(event b occurs) = 3/9 = 1/3

P(a) ∩ P(b) = 1/3 * 1/3 = 1/9

P(b|a) = P(a) ∩ P(b) / P(a)

          =  1/9 / 1/3

          =  1/3.

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Answer:

Since the order of choice matters, we will permute the values.                       a bit more explanation for this:

If the order of choice did NOT matter, ABC and BCA will be counted as one since order of choice does NOT matter

Since order of choice does matter, ABC , BCA and CAB are all different possibilities for the arrangement of the same 3 letters

Since we have 3 slots:

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Now, for the first slot. You can out either one if the 4 alphabets in the first slot since no slot has been used as of now

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Now that one slot has been used, one of the 4 alphabets has been used and since we are not allowed to repeat the same alphabets, we are left with  3 more alphabets

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Now that we know the possible alphabets for all 3 slots, we will multiply them with each other to get the total possible number of 3 - alphabet words we can make with 4 alphabets

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We could've used the formula for Permutation as well

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