Answer:
hello your question is incomplete here is the complete question
Use cylindrical coordinates Find the volume of the solid that lies within both the cylinder x^2 + y^2=16 and the sphere x^2 + y^2 + Z^2= 81
Answer : ![\frac{4 \pi }{3} [729 - 65\sqrt{65} ]](https://tex.z-dn.net/?f=%5Cfrac%7B4%20%5Cpi%20%7D%7B3%7D%20%5B729%20-%2065%5Csqrt%7B65%7D%20%5D)
Step-by-step explanation:
The given data
cylinder = x^2 + y^2 = 16
sphere = x^2 + y^2 +z^2 = 81
from the given data the solid is symmetric around the xy plane hence we will calculate half the solid volume above the plane then multiply the sesult by 2
Note : we are restricting our attention to the cylinder x^2 + y^2 = 16 and also finding the volume inside the sphere which gives bound on the z-coordinate as well
the r parameter goes from 0 to 4
ATTACHED IS THE REMAINING PART OF THE SOLUTION
showing the integration
B. It is vertically stretched by a factor of 4. If you had x^2 versus 4x^2, when x is positive and increasing, 4x^2 is increased by 4 for every value of x.
Answer:
30 cm.
Step-by-step explanation:
Draw a line from R perpendicular to PQ to meet PQ at T.
RQT forms a right-angled triangle with RT = SP = 15.
So tan 36.87 = RT / TQ
tan 36.87 = 15 / TQ
TQ = 15 / tan 36.87
= 20 cm.
Now PT = SR = 10, so
PQ = 10 + 20
= 30 cm.
Answer:
x = 98 mm
Step-by-step explanation:
The angle bisector YT divides the triangle into proportional segments:
VY/VT = KY/KT
Filling in the numbers and multiplying by VT, we have ...
VY/57 = 68/129.2
VY = 57·68/129.2 = 30
Then we can find x from ...
x = VY + YK = 30 +68 = 98 . . . mm
The value of x is 98 mm.
Answer:
C(t) into F(t)=9/5C(t)+32.
6.5.4 it would be F(t)*C(t)=9/5
Step-by-step explanation:
do the cansil out methed then sove it like u would an problues thet ask to sove for x
