Answer:
The number of expected people at the concert is 8,500 people
Step-by-step explanation:
In this question, we are asked to determine the expected number of people that will attend a concert if we are given the probabilities that it will rain and it will not rain.
We proceed as follows;
The probability that it will rain is 30% or 0:3
The probability that it will not rain would be 1 -0.3 = 0.7
Now, we proceed to calculate the number of people that will attend by multiplying the probabilities by the expected number of people when it rains and when it does not rain.
Mathematically this is;
Number of expected guests = (probability of not raining * number of expected guests when it does not rain) + (probability of raining * number of expected guests when it rains)
Let’s plug values;
Number of expected guests = (0.3 * 5,000) + (0.7 * 10,000) = 1,500 + 7,000 = 8,500 people
A sandwich store charges a delivery fee to bring lunch to an office.
Delivery cost - D
Meatball sandwich cost - M
One office pays $40.50 for 5 meatball sandwiches.
40.50 = 5M + D
Another office pays $66.50 for 9 meat ball sandwiches
66.50 = 9M + D
A. How much does each meatball sandwich add to the cost of delivery?
D = 40.50 - 5M = 66.50 - 9M
40.50 - 5M = 66.50 - 9M
9M - 5M = 66.50 - 40.50
4M = 26.00
M = 6.50
B. What is the delivery fee
D = 40.50 - 5M = 40.50 - 5(6.50) = 40.50 - 32.50 = 8.00
Check
66.50 = 9M + D = 9(6.50) + 8 = 58.50 + 8.00 = 66.50
The answer is D. Since the x line is seconds and y is feet traveled it would mean that the train travels 180 feet in 3 seconds
Answer:
The null and alternative hypotheses are:
![H_{0}:\mu=75](https://tex.z-dn.net/?f=H_%7B0%7D%3A%5Cmu%3D75)
![H_{a} : \mu>75](https://tex.z-dn.net/?f=H_%7Ba%7D%20%3A%20%5Cmu%3E75)
Under the null hypothesis, the test statistic is:
![t=\frac{\bar{x}-\mu}{\frac{s}{\sqrt{n}} }](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B%5Cbar%7Bx%7D-%5Cmu%7D%7B%5Cfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%7D%20%7D)
Where:
is the sample mean
is the sample standard deviation
is the sample size
![\therefore t= \frac{83-75}{\frac{9.8206}{\sqrt{10}} }](https://tex.z-dn.net/?f=%5Ctherefore%20t%3D%20%5Cfrac%7B83-75%7D%7B%5Cfrac%7B9.8206%7D%7B%5Csqrt%7B10%7D%7D%20%7D)
![=2.58](https://tex.z-dn.net/?f=%3D2.58)
Now, we can find the right tailed t critical value at 0.01 significance level for df = n-1 = 10 - 1 = 9 using the t distribution table. The t critical value is given below:
Since the test statistic is less than the t critical value, we therefore, fail to reject the null hypothesis and conclude that there is not sufficient evidence to support the claim that the people do better with the new edition.
Step-by-step explanation:
The x are the values that you have been given