3 years ago

Please help me someone? Will give a thanks and award

1 answer:

3 0

The probabilities of knocking down zero, one, and two pins are $0.175, 0.189,$ and $0.264$ , respectively. The total probability of knocking down at most two is thus $0.175+0.189+0.264=0.628$ , or $62.8%$ .

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