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sineoko [7]
3 years ago
9

Joe's age exceeds by Vika's age by 16 years. Four years ago, Joe was twice as old as Vika. Find the present age for each.

Mathematics
1 answer:
____ [38]3 years ago
8 0

Answer:

Joe's present age = 36 years

Vika's present age = 20 years

Step-by-step explanation:

Let us represent the present age of

Joe = x

Vika = y

Joe's age exceeds by Vika's age by 16 years.

x = y + 16...... Equation 1

Four years ago, Joe was twice as old as Vika.

x - 4 = 2(y - 4)

x - 4 = 2y - 8........ Equation 2

We substitute y + 16 for x

y + 16 - 4 = 2y - 8

Collect like terms

16 - 4 + 8 = 2y - y

y = 20 years

We solve for x

x = y + 16...... Equation 1

x = 20 + 16

x = 36 years

Therefore, Joe's present age = 36 years

Vika's present age = 20 years

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The radius of the semicircle in the following composite figure is 8.5 millimeters. What is the total area of the composite figur
nydimaria [60]

Answer:

13.35 millimeter. (About)

Step-by-step explanation:

To find the area or circumference of any circle, you need to use pi. So, if we are trying to fine the area of a <em>semicircle, </em>you use the the formula:

πr²/2

So, if the radius is 8.5,

8.5 · 3.14 = 26.69

Now we divide it by 2.

26.69 = 13.345

Since the question is asking to round to the hundredths, the answer will be 13.35 millimeters.

8 0
3 years ago
Read 2 more answers
Which of the following problems represents the following:
madam [21]

Answer:

D

Step-by-step explanation:

"Turn around phrase" just means that you are subtracting the last number minus the first number. Subtracting the negative number is written as -(-34.7)

5 0
3 years ago
a total eclipse in 2003 lasted 2 17/24,minutes in 2005 it lasted 3/8 of a minute how much longer did it last in 2003
Doss [256]

Answer:

Total eclipse was 2\frac{1}{3} minutes longer than in 2005.

Step-by-step explanation:

It is given in the question that total eclipse in 2003 lasted 2\frac{17}{24} minutes and in 2005 it lasted 3/8 of a minute.

We have to calculate how much longer did it last in 2003.

So we have to subtract the duration in 2003 by duration in 2005

Total time taken in 2003- total time taken in 2005

=2\frac{17}{24}-\frac{3}{8}

\frac{48+17}{24}-\frac{3}{8}

=\frac{65}{24}-\frac{3}{8}

=\frac{65-9}{24}

=\frac{56}{24}

\frac{7}{3}

=2\frac{1}{3} minutes


3 0
3 years ago
Read 2 more answers
Part 2
ahrayia [7]

Answer:

B. 236.3

Step-by-step explanation:

Population density can be found by dividing the number of people by the area of the land.

number of people / land area

The population is 20,510 people and the area is 86.8 square miles.

20,510 people / 86.8 square miles

Divide 20,510 by 86.8

236.290323 people /square mile

Round to the nearest tenth. The 9 in the hundredth place tell us to round the 2 to a 3 in the tenth place.

236.3 people/ square mile

There are 236.3 people per square mile and B is correct.

6 0
3 years ago
(4.161 x 10^2) + (4.56 x 10^3)
VladimirAG [237]
Convert to stand both expressions to standard form:
416.1 + 4,560

Add:
4,976.1
5 0
3 years ago
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