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2 years ago

What is the answer one, two, three, four, five, six,

Mathematics

2 answers:

lesya692 [45]2 years ago

8 0

Answer:

Step-by-step explanation:

1 to any power is itself

aleksley [76]2 years ago

6 0

The answer is x=1
x^5=1
x=5[square]1
x=1

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last year 950 people attended atown's annual parade. this year 1,520 people attended. what was the percent incrase in attendance

Sidana [21]

1520--------------100%
950---------------- x

1520*x = 95000
$x = \frac{95000}{1520}$
$\boxed{x = 62,5}$ %

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3 years ago

What is the value of F(x)=3x-12forx=9?

GrogVix [38]

Answer:

Step-by-step explanation:

3(9)=27

27-12=15

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3 years ago

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sesenic [268]

Flipping a coin should be it

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3 years ago

How do you find the perimeter of any closed figure?

irinina [24]

Answer:

add the lengths of each side of the shape. If there are units, include units in your final result.

Step-by-step explanation:

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3 years ago

Read 2 more answers

Simplify the expression. Assume that all variables represent nonzero real numbers.StartFraction (4 n Superscript 4 Baseline q Su

Alja [10]

Answer:

$\frac{ - 3}{ 256 {q}^{10} {n}^{8} }$

Step by step explanation:

$\frac{ {(4 {n}^{4} {q}^{5})}^{2} {(8 {n}^{4} q)}^{-2} }{ {(- 3 {nq}^{9})}^{ - 1} {(4 {n}^{3} {q}^{9}) }^{3} }$

first we will change the terms with negative superscrips to the other side of the fraction

$\frac{{(4 {n}^{4} {q}^{5})}^{2}{(- 3 {nq}^{9})}^{ 1}}{{(4 {n}^{3} {q}^{9})}^{3} {(8 {n}^{4} q)}^{2} }$

then we will distribute the superscripts

$\frac{ {4}^{2} {n}^{2 \times 4} {q}^{2 \times 5} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{3 \times 3} {q}^{9 \times 3} {8 }^{2}{n}^{4 \times 2} {q}^{2} }$

$\frac{ {4}^{2} {n}^{8} {q}^{10} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{9} {q}^{27} {8 }^{2}{n}^{8} {q}^{2} }$

as when multiplying two powers that have the same base, we can add the exponents and, to divide podes with the same base, we can subtract the exponents

${4}^{2 - 3} {q}^{10 + 9 - 2 - 27} {n}^{8 + 1 - 8 - 9} {8}^{ - 2} { (- 3)}^{1}$

${4}^{ - 1} {q}^{ - 10} {n}^{ - 8} {8}^{ - 2} { (- 3)}^{1}$

then we will change again the terms with negative superscrips to the other side of the fraction

$\frac{ - 3}{ 4 \times {8}^{2} {q}^{10} {n}^{8} }$

$\frac{ - 3}{ 256 {q}^{10} {n}^{8} }$

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3 years ago