Since sine and cosecant are reciprocals, when one has a maximum the other has a minimum and vice versa.
That's choices B & D
Not sure what the question at the end is asking; at 90 degrees and also at -90 degrees the values of sine and cosecant are equal.
<span>Answers:
(12x^2 + 3x + 6) + (-7x^2 – 4x – 2) = 5x^2 - x + 4
(2x2 – x) + (-x – 2x2 – 2) = -2x - 2
(x3 + x2 + 2) + (x2 – 2 – x3) = 2x^2
(x2 + x) + (x2 + 8x – 2) = 2x^2 + 9x - 2
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Answer:
<h2>-1</h2>
Step-by-step explanation:
Quick answer I don't think this has an answer.
If you take the cos-1(2 sqrt(2)) your calculator should have a fit. Let's check that out. Mine certainly does. So there is something wrong with the question. If there is something to add in please do it and I will it least put an answer in the comments. As it stands, nothing will work.
If you put your calculator in radians, you will get an answer but it will not be anything resembling the choices you've listed.
If you meant sqrt(2) / 2 that would give 45o. Put it in your calculator like this 2 ^ 0.5 divided by 2 = 0.707
Cos - 1 (0.707) = 45
