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Anon25 [30]
3 years ago
5

Please Help: Solve for x x + 11 = 5x - 5

Mathematics
2 answers:
Alchen [17]3 years ago
7 0
The final answer is x=4. you have to solve for x so you must get X alone. start by adding the 5 to both sides, making the equation x+16=5x. then, subtract x from both sides. 16=5x-x which becomes 16=4x. divide both sides by 4 to get x alone and you get x=4.
Brums [2.3K]3 years ago
6 0
 the answer for this question is x=4
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25 points:)<br><br> question 2-3
Furkat [3]

Answer:

2) r=73

Step-by-step explanation:

all 4 sided shapes add up to 360.

so 90+90=180

180+107=287

360-287=73

so r=73

4 0
4 years ago
The candy shop puts 10 ounces of gummy bears in each box. How many
Nostrana [21]
Hi! You need 3 boxes because if you divide 21 1/4 / 10 you get 2 1/8 or 2.125 so you at least have two boxes. You will still have some left over after the two boxes so you will need another box for those. I hope this helped, Goodluck :)
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3 years ago
5.) Orange juice concentrate is mixed with water in a ratio of 1 to 3. How much water
vladimir1956 [14]

Answer:

2 to 6

Step-by-step explanation:

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6 0
3 years ago
Given that (ax^2 + bx + 3) (x + d) = x^3 + 6x^2 + 11x + 12<br> a + 2b - d = ?
Mariulka [41]

Answer:

Let's solve for a.

(ax2+bx+3)(x+d)=x3+6x2+11x+12a+2b−d

Step 1: Add -12a to both sides.

adx2+ax3+bdx+bx2+3d+3x+−12a=x3+6x2+12a+2b−d+11x+−12a

adx2+ax3+bdx+bx2−12a+3d+3x=x3+6x2+2b−d+11x

Step 2: Add -bdx to both sides.

adx2+ax3+bdx+bx2−12a+3d+3x+−bdx=x3+6x2+2b−d+11x+−bdx

adx2+ax3+bx2−12a+3d+3x=−bdx+x3+6x2+2b−d+11x

Step 3: Add -bx^2 to both sides.

adx2+ax3+bx2−12a+3d+3x+−bx2=−bdx+x3+6x2+2b−d+11x+−bx2

adx2+ax3−12a+3d+3x=−bdx−bx2+x3+6x2+2b−d+11x

Step 4: Add -3d to both sides.

adx2+ax3−12a+3d+3x+−3d=−bdx−bx2+x3+6x2+2b−d+11x+−3d

adx2+ax3−12a+3x=−bdx−bx2+x3+6x2+2b−4d+11x

Step 5: Add -3x to both sides.

adx2+ax3−12a+3x+−3x=−bdx−bx2+x3+6x2+2b−4d+11x+−3x

adx2+ax3−12a=−bdx−bx2+x3+6x2+2b−4d+8x

Step 6: Factor out variable a.

a(dx2+x3−12)=−bdx−bx2+x3+6x2+2b−4d+8x

Step 7: Divide both sides by dx^2+x^3-12.

a(dx2+x3−12)

dx2+x3−12

=

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

a=

−bdx−bx2+x3+6x2+2b−4d+8x

dx2+x3−12

Answer:

a=

−bdx−bx2+x3+6x2+2b−4d+8x/

dx2+x3−12

Step-by-step explanation:

8 0
3 years ago
Express 18 as a product of its factors?​
Dimas [21]

Answer:

18= 2 x 3 x 3

Step-by-step explanation:

Basically, we branch out 18 into its prime factors. So, the prime factorization of 18 is 18= 2 × 3 × 3. A factor tree is not unique for a given number. Instead of expressing 18 as 2 × 9, we can express 18 as 3 × 6.

7 0
2 years ago
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