You <em>multiply</em> both sides of the first equation by 4.
Then you have . . .
-2x + 4y = 3 and y - 2x = 3 .
If you want to get rid of a fraction, you multiply it by itsdenominator.
BUT ... whatever you do to one term on one side of the equation, you
have to do the same to <em>all</em> the terms on that side, AND then you have to
do the same thing to all the termson the OTHER side.
Answer: y = -2x + 1 or y +2x - 1 = 0
Step-by-step explanation
Recall, equation of a line passing through two coordinates is
y - y₁ = y₂ - y₁ ( x - x₁ )
₋₋₋₋₋₋₋₋ x
x₂ - x₁
note , (x₁ = -3), (x₂ = 1), (y₁ = 7), (y₂ = -1)
Now substitute for those values in the above equation
y - (7) = -1 - 7
------ X ( x - (-3)
1 - (-3)
y - 7 = -8/4 X ( x + 3 )
y - 7 = -2(x + 3 )
y - 7 = -2x - 6
The equation now
y = -2x -6 + 7
y = -2x + 1 or
y + 2x - 1 = 0.
Answer:
Step-by-step explanation:
So, to start, we need to label all the values. This is
16, 17, 17, 17, 18, 18 , 18 , 18, 18, 18, 19, 19, and 20.
The Lower Quartile can be found if you know the median. The median in this case is 18. So, the Lower Quartile is just median between the median and the lowest number. So it is the median between 18 and 16. Not average, but the median in the set. In this case it is 17. The Upper Quartile is the same except now it is between the median and highest value, or 18.5. The IQR is found by subtracting the Upper by the Lower, or 18.5-17, or 1.5.
Reduce the fractions then do the math I always forget to flip the fraction then multiply it by the fraction it already was
Answer:
B= 50
Step-by-step explanation:
