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castortr0y [4]
2 years ago
14

Need help !! 25 points ​

Mathematics
1 answer:
lyudmila [28]2 years ago
6 0

Answer:

B

Step-by-step explanation:

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Please help me with this math question and thank you to those who can and will help me.
Roman55 [17]

Answer: B plz mark me bralny

Step-by-step explanation:

3 0
3 years ago
HELP FOR BREANTEST ANSWER ON PAPER
nevsk [136]

Answer:

3 3/7

Step-by-step explanation:

2 = 14/7

14/7 + 10/7 = 24/7

24/7 simplified is 3 3/7

8 0
2 years ago
Each question on a multiple-choice exam has four choices. One of the choices is correct, worth four points. Another choice is wr
kifflom [539]

Answer:A)0.75

Step-by-step explanation:

Given

There are four options to a question

out of which one is correct with 4 points

one is wrong but carries 1 point

Other two are wrong with a negative Point

Probability of selecting an option is \frac{1}{4}

Expected score=\frac{1}{4}\times 4+\frac{1}{4}\times 1+\frac{1}{4}\times (-1)+\frac{1}{4}\times (-1)

Expected score=1+0.25-0.5

Expected score=0.75

8 0
2 years ago
Find the sum of 1 + 3/2 + 9/4 + …, if it exists.
zmey [24]

Answer:

Option (4)

Step-by-step explanation:

Given sequence is,

1+\frac{3}{2}+\frac{9}{4}..........

We can rewrite this sequence as,

1+\frac{3}{2}+(\frac{3}{2})^2.............

There is a common ratio between the successive term and the previous term,

r = \frac{\frac{3}{2}}{1}

r = \frac{3}{2}

Therefore, it's a geometric sequence with infinite terms. In other words it's a geometric series.

Since sum of infinite geometric sequence is represented by the formula,

S_{n}=\frac{a}{1-r}  , when r < 1

where 'a' = first term of the sequence

r = common ratio

Since common ratio of the given infinite series is greater than 1 which makes the series divergent.

Therefore, sum of infinite terms of a series will be infinite Or the sum is not possible.

Option (4) will be the answer.

3 0
3 years ago
What is the simplified form of (5x^3 + 2)(5x^3 -2)
lapo4ka [179]

Simplify the expression.

25x6−4

plz mark me as brainliest :)

8 0
3 years ago
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