Question

What is the y-intercept of the quadratic function f(x) = (x – 8)(x + 3)? (8,0) (0,3) (0,–24) (–5,0)

Answer 1

The correct answer is:  [C]:  " (0, 24) " .
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Explanation:
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Given the quadratic function:
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          →  "  y = (x − 8) (x + 3) "  ;   ←  Note:  Replace the "f(x)" with: "y" ; 

→  Find the "y-intercept".
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→  Note:  The "y-intercept" is the coordinate of the point(s) of the graph of the equation at which the graph crosses the "x-axis" when "x = 0" . 

   → So;  we set plug in "0" for "x" into our equation; and solve for "y" ; 

          → " y = (x − 8) (x + 3) " ;

          →   y = (0 − 8) (0 + 3)  ; 

          →   y = (-8) * (3)  ;  
 
          →   y = - 24 ; 
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So, the "y -intercept" of the given quadratic function is:
 
the point at which:  "x = 0 ; y = -24 " ;

      →  that is; the point  the coordinates:  " (0, - 24) " ;
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  →  which is:  Answer choice:  [C]:  " (0, - 24) " .
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Answer 2

Answer:

The correct answer is:  [C]:  " (0, 24) " .

Step-by-step explanation:

Given the quadratic function:

 ote:  Replace the "f(x)" with: "y" ; 

→  Find the "y-intercept".

→  Note:  The "y-intercept" is the coordinate of the point(s) of the graph of the equation at which the graph crosses the "x-axis" when "x = 0" . 

  → So;  we set plug in "0" for "x" into our equation; and solve for "y" ; 

         → " y = (x − 8) (x + 3) " ;

         →   y = (0 − 8) (0 + 3)  ; 

         →   y = (-8) * (3)  ;  

         →   y = - 24 ; 

So, the "y -intercept" of the given quadratic function is:

the point at which:  "x = 0 ; y = -24 " ;

     →  that is; the point  the coordinates:  " (0, - 24) " ;