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Serhud [2]
3 years ago
7

What is 60/8 as a mixed number

Mathematics
2 answers:
Maksim231197 [3]3 years ago
6 0
8x7=56
56+4=60


7 1/2 
 hope it helped!
Katena32 [7]3 years ago
6 0
7and one half
Hope it helps
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(x+2)(x+5) find the following products by using distributive property
nika2105 [10]

Answer:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

(

x

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5

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becomes:

(

x

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We can now combine like terms:

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Step-by-step explanation:

7 0
3 years ago
On a final exam, each multiple-choice question is worth 4 points and each word problem is worth 8 points. Lorenzo needs at least
PolarNik [594]
Each multiple choice is worth 4 points, and X is the number of questions he get's right. For example, he gets 3 right: 4 x 3 = 12 points in total.
The same goes for the <span>word problems. Y represent the </span><span>the number of correct answers so, for example: he gets 4 right and each one is worth 8 points: 8x4
</span> 
Since he needs to have a least 50 points, that means that he can have 50 or more than that. That can be written as: <span>≥

So, as i explained, the only possible option is D.</span>
<span> 4x + 8y ≥ 50 </span>
8 0
3 years ago
Read 2 more answers
What number has 2 more tens than 40 and the same number of ones as 18
Juli2301 [7.4K]
The answer is 68.
To solve 2 more tens than 40, you add 20 to 40, which is 60.
To solve for the same number of ones as 18, then it would only be 68.

Hope this helps!!
5 0
3 years ago
Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it. lim x→1 3x x − 1
Reika [66]

Answer:

<h2>3/2</h2>

Step-by-step explanation:

Given the limit of a function expressed as \lim_{x \to 1} (\dfrac{3x}{x-1} - \dfrac{3}{lnx}), we are to evaluate it. To evaluate it, we will simply substitute x = 1 into the function since the variable x tends to 1.

\lim_{x \to 1} (\dfrac{3x}{x-1} - \dfrac{3}{lnx})\\\\= (\dfrac{3(1)}{1-1} - \dfrac{3}{ln1})\\\\= \dfrac{3}{0} - \dfrac{3}{0}\\\\= \infty - \infty (ind)

Since we got an indeterminate function, we will find the LCM of the function and solve again.

= \lim_{x \to 1} (\dfrac{3x}{x-1} - \dfrac{3}{lnx})\\\\= \lim_{x \to 1} \dfrac{3xlnx-3(x-1)}{(x-1)lnx}\\\\\\= \dfrac{3(1)ln(1)-3(1-1)}{(1-1)ln1}\\\\= \frac{3(0)-3(0)}{0(0)} \\\\= \frac{0}{0} (ind)

Applying L'hospital rule;

\frac{x}{y} = \lim_{x \to 1} \dfrac{d/dx(3xlnx-3(x-1))}{d/dx((x-1)lnx)}\\\\=  \lim_{x \to 1} \dfrac{3x(\frac{1}{x})+ 3lnx-3)}{(x-1)\frac{1}{x} +lnx}\\\\= \lim_{x \to 1} \dfrac{3 + 3lnx-3}{(x-1)\frac{1}{x} +lnx}\\\\= \frac{3ln1}{(1-1)\frac{1}{1} +ln1}\\\\= \frac{0}{0} (ind)

Applying L'hospital rule again;

= \lim_{x \to 1} \dfrac{\frac{d}{dx} (3lnx)}{\frac{d}{dx} ((x-1)\frac{1}{x} +lnx)}\\\\=  \lim_{x \to 1} \dfrac{\frac{3}{x} }{(x-1)\frac{-1}{x^2} + \frac{1}{x} +\frac{1}{x} }\\\\= \dfrac{\frac{3}{1} }{(1-1)\frac{-1}{1^2} + \frac{1}{1} +\frac{1}{1} }\\\\= \frac{3}{0(-1)+2}\\ \\= \frac{3}{2-0}\\ \\= 3/2

<em>Hence the limit of the function is 3/2.</em>

7 0
4 years ago
If the measure of angle 1 is 45°, what is the measure of angle 11 in degrees.
miskamm [114]
120 degrees I hope you’re helping
8 0
3 years ago
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